PHP循环内返回数组

Question

我正在创建一个遍历记录的函数，我想返回项目数组

if(!function_exists("TicketAttachments")) {
    function TicketAttachments($update_sequence) {
        global $conn, $pdo_conn;

        $results = array();
        $sql="SELECT * from ticket_updates where ticketnumber = '".$update_sequence."' and type = 'attachment' ";
        $rs=mysql_query($sql,$conn);
        while($result=mysql_fetch_array($rs)) {
            $results["link"] = 'media/ticket_attachments/'.$result["notes"];
            $results["name"] = $result["notes"];
        }

        return $results;
    }
}

我在这里称呼它：

$attachments = TicketAttachments($TicketUpdate["sequence"]);
foreach($attachments as $att) {
    echo $att["name"];
}

但这回响了h5而名称= 55388-20150929124302-screen dump 28092015.docx

Answer 1

我认为你需要结合数组

if(!function_exists("TicketAttachments")) {
    function TicketAttachments($update_sequence) {
        global $conn, $pdo_conn;

        $results = array();
        $sql="SELECT * from ticket_updates where ticketnumber = '".$update_sequence."' and type = 'attachment' ";
        $rs=mysql_query($sql,$conn);
        while($result=mysql_fetch_array($rs)) {
            $results[] = array(
                "link"=>'media/ticket_attachments/'.$result["notes"],
                "name" => $result["notes"];
            );
        }
        return $results;
    }
}