php多个文件上传，file_exist

Question

我是PHP编程的新手，我正在尝试制作多文件上传脚本，但是我不知道如何检查上传文件是否已存在！ 我怎样才能做到这一点？ 你能帮助我吗？ 这是我的代码：

 <form action="upload.php" method="post" enctype="multipart/form-data"> <input type="file" name="files[]" multiple> <input type="submit" value="Upload"> </form> foreach($_FILES['files']['name'] as $i => $name) { $name = $_FILES['files']['name'][$i]; $size = $_FILES['files']['size'][$i]; $type = $_FILES['files']['type'][$i]; $tmp = $_FILES['files']['tmp_name'][$i]; $explode = explode('.', $name); $ext = end($explode); $path = 'uploads/'; $path = $path . basename( $explode[0] . time() .'.'. $ext); $errors = array(); if(empty($_FILES['files']['tmp_name'][$i])) { $errors[] = 'Please choose at least 1 file to be uploaded.'; } if(empty($errors)) { if(!file_exists('uploads')) { mkdir('uploads', 0777); } if(move_uploaded_file($tmp, $path)) { echo '<p>The file <b>'.$name.'</b> successfully uploaded</p>'; }else { echo 'Something went wrong while uploading the file <b>'.$name.'</b>'; } }else { foreach($errors as $error) { echo '<p>'.$error.'<p>'; } } } ?> 

Answer 1

如果文件在目录中，则file_exists返回true。 因此，如果要检查file_exist的条件，则必须将move_uploaded_file保留在其中。

有关更多信息，请检查此文件是否存在-W3 Schools

    <form action="upload.php" method="post" enctype="multipart/form-data">
        <input type="file" name="files[]" multiple>
        <input type="submit" value="Upload">
    </form>

    foreach($_FILES['files']['name'] as $i => $name)
    {

        $name = $_FILES['files']['name'][$i];
        $size = $_FILES['files']['size'][$i];
        $type = $_FILES['files']['type'][$i];
        $tmp = $_FILES['files']['tmp_name'][$i];

        $explode = explode('.', $name);

        $ext = end($explode);

        $path = 'uploads/';
        $path = $path . basename( $explode[0] . time() .'.'. $ext);

        $errors = array();

        if(empty($_FILES['files']['tmp_name'][$i])) {
            $errors[] = 'Please choose at least 1 file to be uploaded.';
        }
        if(empty($errors)) 
        {

            if(!file_exists($path))
            {

                if(move_uploaded_file($tmp, $path)) 
                {
                    echo '<p>The file <b>'.$name.'</b> successfully uploaded</p>';
                }
                else
                {
                    echo 'Something went wrong while uploading the file <b>'.$name.'</b>';
                }
            }
        }
        else
        {
            foreach($errors as $error)
            {
                echo '<p>'.$error.'<p>';
            }
        }

    }

Answer 2

考虑到您给他们取了随机名称，这很难做到。 如果您使用的是数据库，请考虑保存文件md5并检查是否已拥有它。

否则，您可以使用md5作为文件名保存文件。

这是获取文件的md5的方法：

md5_file($tmp)

Answer 3

您可以尝试以下方法。 它使用一个简单的preg_match函数调用来查看是否有一个名称相同的文件减去时间戳。

<?php

    $errors = array();
    $path = 'uploads/';

    /* Check if the target directory exists - no need to do it repeatedly */
    if( !file_exists( $path ) ) mkdir( $path, 0777 );
    /* file_exists results are cached */
    clearstatcache();


    foreach( $_FILES['files']['name'] as $i => $name ) {
        if( !empty( $_FILES['files']['tmp_name'][$i] ) ) {
            $name = $_FILES['files']['name'][$i];
            $size = $_FILES['files']['size'][$i];
            $type = $_FILES['files']['type'][$i];
            $tmp  = $_FILES['files']['tmp_name'][$i];

            $ext=pathinfo( $name, PATHINFO_EXTENSION );
            $basename=pathinfo( $name, PATHINFO_FILENAME );
            $filepath = $path . $basename . time() . '.' . $ext;
            $pttn='@'.$basename.'\d{10}@';

            /* Does a file, with the name of the original, exist? */
            if( preg_match( $pttn, implode( '', glob( $path .'*.*' ) ) ) ){
                /* Files already exist */   
            } else {
                $result=@move_uploaded_file( $tmp, $filepath );
                echo $result ? '<p>The file <b>'.$name.'</b> successfully uploaded</p>' : 'Something went wrong while uploading the file <b>'.$name.'</b>';
            }
        } else {
            $errors[] = 'Please choose at least 1 file to be uploaded.';
        }
    }
    if( !empty( $errors ) ) echo implode( '<br />', $errors );

?>