我如何在 php 中使用 in_array 检查字符串“患者”

Question

我的数组是：

$com_arr = Array(
    [0] => patient
    [1] => novel
    [2] => name
    [3] => monkey
    [4] => yourself
    [5] => novel
    [6] => buttons
    [7] => fifth
    [8] => stories
    [9] => English
    [10] => sign
    [11] => children
)

和变量$values_for_ex[$r-1] = patient和我的函数看起来像

if(in_array($values_for_ex[$r-1] ,$com_arr)) {   
     $replacements1 = "<span style='color:green;font-weight:700;' id='s'>"
                    . $values_for_ex[$r-1] . "</span>";
}

但条件不起作用..为什么？

Answer 1

这是更正后的代码。 出于测试目的，我假设$r的值为 5。

$com_arr = array(
'patient',
'novel',
'name',
'monkey',
'yourself',
'novel',
'buttons',
'fifth',
'stories',
'English',
'sign',
'children'
);
$r=5;// hard-coded for testing purpose
$values_for_ex[$r-1] = "patient";
if(in_array($values_for_ex[$r-1] ,$com_arr)) {   
$replacements1 = "<span style='color:green;font-weight:700;' id='s'>". $values_for_ex[$r-1] . "</span>";
    echo $replacements1;
}