[英]how to access parent project's classes in sub project in playFramework 2.3.x
我正在使用play 2.3.8并使用此gudie在我的项目中创建子项目,我创建了子项目“ mySubProject”,然后在月食中将项目导入了父项目myParentProject
和mySubProject
现在我首先有两个问题->这是否正确首先,我进口myParentProject
在日食的话,我进口mySubProject
二线>在我mySubProject
我可以访问的类myParentProject
并导入了包,但mySubProject
当我要访问我的类/包myParentProject
它不会让我这样做,它显示错误Object not found
是根项目myParentProject
文件
name := """myParentProject"""
version := "1.0-SNAPSHOT"
lazy val root = (project in file(".")).enablePlugins(PlayScala)
.aggregate(mySubProject)
.dependsOn(mySubProject)
scalaVersion := "2.11.1"
fork in run := true
javaOptions in run ++= Seq("-J-Xms1G", "-J-Xmx2G")
val appDependencies = Seq(
// Add your project dependencies here,
"org.scalatestplus" %% "play" % "1.2.0" % "test"
)
lazy val mySubProject = project
libraryDependencies ++= Seq("org.scalatest" %% "scalatest" % "2.2.1" % "test"withSources() withJavadoc(),
"com.esotericsoftware.kryo" % "kryo" % "2.10",
"org.mongodb" %% "casbah" % "2.8.0",
"org.slf4j" % "slf4j-api" % "1.6.4",
"org.elasticsearch" % "elasticsearch" % "1.6.0",
"org.codehaus.groovy" % "groovy-all" % "2.4.0",
"org.apache.lucene" % "lucene-expressions" % "4.10.4",
"org.scalatest" %% "scalatest" % "2.2.1" % "test"withSources() withJavadoc(),
"org.easymock" % "easymock" % "3.1" withSources() withJavadoc(),
"org.mockito" % "mockito-all" % "1.9.5",
"com.typesafe.akka" %% "akka-actor" % "2.3.6",
"ch.qos.logback" % "logback-core" % "1.0.9",
"com.github.nscala-time" %% "nscala-time" % "2.0.0",
"net.liftweb" %% "lift-json" % "2.6+",
"net.liftweb" %% "lift-json" % "2.6+",
"com.hazelcast" % "hazelcast" % "3.5",
"com.hazelcast" % "hazelcast-client" % "3.5",
"com.twitter" % "chill-bijection_2.11" % "0.7.0"
//,"com.codahale" % "jerkson_2.9.1" % "0.5.0"
)
这是子项目mySubProject
构建文件
name := """mySubProject"""
version := "1.0-SNAPSHOT"
scalaVersion := "2.11.1"
libraryDependencies ++= Seq("org.scalatest" %% "scalatest" % "2.2.1" % "test"withSources() withJavadoc(),
"org.slf4j" % "slf4j-api" % "1.6.4",
"org.elasticsearch" % "elasticsearch" % "1.6.0",
"org.codehaus.groovy" % "groovy-all" % "2.4.0",
"org.apache.lucene" % "lucene-expressions" % "4.10.4",
"org.easymock" % "easymock" % "3.1" withSources() withJavadoc(),
"org.mockito" % "mockito-all" % "1.9.5",
"com.typesafe.akka" %% "akka-actor" % "2.3.6",
"ch.qos.logback" % "logback-core" % "1.0.9",
"com.github.nscala-time" %% "nscala-time" % "2.0.0",
"net.liftweb" %% "lift-json" % "2.6+",
"net.liftweb" %% "lift-json" % "2.6+")
这是我的父项目myParentProject
的代码,我创建了一个名为app / myPackagae / abc.scala的类,这是代码
package myPackagae
import mySubProject._
class abc {
def helloAbc()={
println(" i am root project and i am class abc ")
}
val test=new Testing
test.helloTesting()
}
在mySubProject
我在mySubProject
创建了一个类,这里是代码
package mySubProject
//import parentProjectPackage._
import myPackagae._ //here is an error not found: object myPackagae
class Testing {
def helloTesting() ={
println("i am a subproject or child project and i am class Testing")
}
//and here i want to access class abc and its method helloAbc() but eclipse is not importing
}
请指导我如何在子项目中导入根项目的包/类
这是一个古老的问题,但仍被认为是一个答案。
TLDR :
通常避免将根项目导入子项目,除非您确定根项目不依赖于子项目(例如,您可以将根路由设置为子模块,这是一个依赖项)。
详细答案 :
以下是我关注的项目结构:
- root
- app
- controllers
- models
- modules
- moduleone
- build.sbt
- app
- controllers.moduleone
- models.moduleone
- ...
- moduletwo
- build.sbt
- app
- controllers.moduletwo
- ...
- build.sbt
以下是根项目build.sbt文件。 注意子项目的dependsOn设置,它基本上将根项目作为依赖项添加到子项目,因此您可以将根项目类导入子项目。
lazy val modelone: Project = project.in(file("modules/moduleone"))
.enablePlugins(PlayScala)
.settings(
name := "module-one",
libraryDependencies ++= common
)
.dependsOn(root)
////*******************************
//// Root module
////*******************************
val root: Project = project.in(file("."))
.enablePlugins(PlayScala)
.settings(
name := "root",
libraryDependencies ++= common
)
在子项目中,您可以执行以下操作:
package models.moduleone
import models.SOMETHING_FROM_ROOT_PROJECT
...
将根项目和子项目定义为不同的包是一个好主意,这样可以使导入更加清晰。
还要注意,您应该避免子项目和根项目之间的依赖循环。 我见过一些项目,其中根项目依赖于子项目的某些功能。 在这种情况下,您将为根项目添加dependsOn
,但是如果您的子项目也做同样的事情,它将无法编译。
一个更常见的情况是,您通常最终会在根路由中这样做:
-> /api/moduleone moduleone.Routes
这会将相关流量路由到moduleone。 现在,需要做的是首先编译moduleone,然后在根项目中使用该路由,这意味着根build.sbt必须为:
val root: Project = project.in(file("."))
.enablePlugins(PlayScala)
.dependsOn(moduleone)
.aggregate(moduleone)
.settings(
libraryDependencies ++= common
)
如果然后将根项目导入到moduleone中,它将变成一个循环,它将永远不会编译。
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