将对象数组转换为Object的最佳方法是什么？

Question

我需要将对象数组转换为对象。 我已经完成了以下逻辑。 有没有最好的方法来处理这个？

提琴手版

 var before = [{ "x": ["2015-10-14T01:59:59.999+05:30", "2015-10-14T03:59:59.998+05:30", "2015-10-14T05:59:59.997+05:30", "2015-10-14T07:59:59.996+05:30", "2015-10-14T09:59:59.995+05:30", "2015-10-14T11:59:59.994+05:30", "2015-10-14T13:59:59.993+05:30", "2015-10-14T15:59:59.992+05:30", "2015-10-14T17:59:59.991+05:30", "2015-10-14T19:59:59.990+05:30", "2015-10-14T21:59:59.989+05:30", "2015-10-14T23:59:59.988+05:30"] }, { "CleanCoal": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Middelings": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Prime": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "SpiralProd": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }]; var after = {}; for (var i = 0; i < before.length; i++) { var keys = Object.keys(before[i]); after[keys] = before[i][keys]; } console.log(after) document.writeln(JSON.stringify(after)) 

Answer 1

您可以使用forEach迭代数组，如果对象内部有多个元素，则忘记迭代嵌套数组。

因此，有问题的代码不适用

var arr = [{'a': 'b', 'c': 'd'}];

演示

 var before = [{ "x": ["2015-10-14T01:59:59.999+05:30", "2015-10-14T03:59:59.998+05:30", "2015-10-14T05:59:59.997+05:30", "2015-10-14T07:59:59.996+05:30", "2015-10-14T09:59:59.995+05:30", "2015-10-14T11:59:59.994+05:30", "2015-10-14T13:59:59.993+05:30", "2015-10-14T15:59:59.992+05:30", "2015-10-14T17:59:59.991+05:30", "2015-10-14T19:59:59.990+05:30", "2015-10-14T21:59:59.989+05:30", "2015-10-14T23:59:59.988+05:30"] }, { "CleanCoal": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Middelings": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Prime": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "SpiralProd": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }]; var after = {}; before.forEach(function(obj) { // obj here is the element of the array, ie object // Looping over all the keys of the object Object.keys(obj).forEach(function(key) { // key here is the key of the object after[key] = obj[key]; }); }); console.log(after); document.writeln('<pre>' + JSON.stringify(after, 0, 2) + '</pre>'); 

Answer 2

我们在JavaScript中使用最好的函数式编程：

使用reduce我们不需要将临时变量添加到外部作用域。

for (var i in obj)通常比Obj.keys(obj).forEach ： https ： Obj.keys(obj).forEach

 var before = [{ "x": ["2015-10-14T01:59:59.999+05:30", "2015-10-14T03:59:59.998+05:30", "2015-10-14T05:59:59.997+05:30", "2015-10-14T07:59:59.996+05:30", "2015-10-14T09:59:59.995+05:30", "2015-10-14T11:59:59.994+05:30", "2015-10-14T13:59:59.993+05:30", "2015-10-14T15:59:59.992+05:30", "2015-10-14T17:59:59.991+05:30", "2015-10-14T19:59:59.990+05:30", "2015-10-14T21:59:59.989+05:30", "2015-10-14T23:59:59.988+05:30"] }, { "CleanCoal": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Middelings": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Prime": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "SpiralProd": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }]; var after = before.reduce(function(dst, src){ // import every key: val in src into dst // and keep doing it for every element in the array. for (var key in src) if ({}.hasOwnProperty.call(src, key)) dst[key] = src[key]; return dst; }, {}); // start with an empty object to avoid modifying items in before array. document.writeln("<pre>" + JSON.stringify(after, null, 4) + "</pre>") 

Answer 3

在最新的浏览器[ecmascript 5]中，我们有reduce返回一个对象

试试下面

 var before = [{"x":["2015-10-14T01:59:59.999+05:30","2015-10-14T03:59:59.998+05:30","2015-10-14T05:59:59.997+05:30","2015-10-14T07:59:59.996+05:30","2015-10-14T09:59:59.995+05:30","2015-10-14T11:59:59.994+05:30","2015-10-14T13:59:59.993+05:30","2015-10-14T15:59:59.992+05:30","2015-10-14T17:59:59.991+05:30","2015-10-14T19:59:59.990+05:30","2015-10-14T21:59:59.989+05:30","2015-10-14T23:59:59.988+05:30"]},{"CleanCoal":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]},{"Middelings":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]},{"Prime":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]},{"SpiralProd":["0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00","0.00"]}]; var object = before.reduce(function(o, v, i) { o[i] = v; return o; }, {}); console.log(object); 

在这里小提琴http://jsfiddle.net/pscytrgj/

Answer 4

你可以通过JSON.stringify()来做到这JSON.stringify()

 var before = [{ "x": ["1", "2"], y: { a: 3 } }, { "CleanCoal": ["0.00", "0.00"], b: 4 }, { "Middelings": ["0.00", "0.00"] }, { "Prime": ["0.00", "0.00", "0.00"] }, { "SpiralProd": ["0.00", "0.00", "0.00"] }]; var after = {}; var b = "", i = -1; while (before[++i]) { var str = JSON.stringify(before[i]); b += str.slice(1, str.length - 1); if (before[i + 1]) b += ","; } after = JSON.parse("{" + b + "}"); console.log(after); document.write("<pre>" + JSON.stringify(after, 0, 3) + "</pre>") 

Answer 5

Object.assign怎么样？

 var before = [{ "x": ["2015-10-14T01:59:59.999+05:30", "2015-10-14T03:59:59.998+05:30", "2015-10-14T05:59:59.997+05:30", "2015-10-14T07:59:59.996+05:30", "2015-10-14T09:59:59.995+05:30", "2015-10-14T11:59:59.994+05:30", "2015-10-14T13:59:59.993+05:30", "2015-10-14T15:59:59.992+05:30", "2015-10-14T17:59:59.991+05:30", "2015-10-14T19:59:59.990+05:30", "2015-10-14T21:59:59.989+05:30", "2015-10-14T23:59:59.988+05:30"] }, { "CleanCoal": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Middelings": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "Prime": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }, { "SpiralProd": ["0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00", "0.00"] }]; var after = {}; before.map(function(i){ return Object.assign(after,i); }) console.log(after) document.writeln(JSON.stringify(after))