使用PHP验证表单时出现问题

Question

我正在为我的网站编写一份简短的联系表，但遇到一些问题。 一切都可以正常显示，但是除了未定义变量的通知（因为我使用$ post [$ value]将数据保留在表单输入中）之外，验证完全不再起作用。 我已经将其与之前编写的功能代码进行了比较，但是没有发现任何明显的不同。 这是表格的代码：

<?php
$labels = array("first_name" => "First Name:",
                "last_name" => "Last Name:",
                "company" => "Company*:",
                "email" => "Email:",
                "phone" => "Phone Number*:",
                "subject" => "Subject:",
                "message" => "Message:");
$submit = "Submit";
?>

...

<?php
echo $error_message;
?>
<form method="post">
<table class="contact">
<?php
foreach($labels as $label => $field)
{
    if($label != "message")
    {
        echo "<tr><td class='label'>$field</td>
        <td class='input'><input type='text' maxlength='64' value='".$_POST[$label]."'></td>
        <td class='error'>$error_array[$label]</td></tr>";
    }
    else {
        echo "<tr><td class='label'>$field</td>
        <td class='input'><textarea cols='25' rows='6'>".$_POST[$label]."</textarea></td>;
        <td class='error'>$error_array[$label]</td></tr>";
    }
}
echo "<tr><td class='submit'><input type='hidden' name='submitted' value='yes'>
        <input type='submit' value='$submit'></td></tr>";
?>
</table>
</form>

这是验证它的代码。

<?php
$error_message = "";
$error_array = array();
if(isset($_POST['submitted']) and $_POST['submitted'] == "yes")
{
    foreach($_POST as $field => $value)
    {
        $name_patt = "/^[A-Za-z' -]{1,50}/";
        $phone_patt = "/^[0-9)(xX -]{7,20)$/";
        $addr_patt = "/^[A-Za-z0-9 .,'-]{1,50}$/";
        $email_patt = "/^.+@.+\\..+$/";
        if(preg_match("/first_name/i",$field))
        {
            if(!preg_match($name_patt,$value))
            {
                $error_array['first_name'] = "Please enter a valid first name.";
            }
        }
        if(preg_match("/last_name/i",$field))
        {
            if(!preg_match($name_patt,$value))
            {
                $error_array['last_name'] = "Please enter a valid last name.";
            }
        }
        if(preg_match("/email/i",$field))
        {
            if(!preg_match($email_patt,$value))
            {
                $error_array['email'] = "Please enter a valid email address.";
            }
        }
        if(preg_match("/subject/i",$field))
        {
            if(!preg_match($addr_patt,$value))
            {
                $error_array['subject'] = "Please enter a subject.";
            }
        }
        if(preg_match("/message/i",$field))
        {
            if(empty($_POST['message']))
            {
                $error_array['message'] = "Please enter a message.";
            }
        }
    }
    if(@sizeof($error_array >0))
    {
        include "contact.php";
        $error_message = "<p class='error'>One or more fields has been filled incorrectly.</p>";
        exit();
    }
    else
    {
        echo "Success!";
    }
}
else
{
    include "contact.php";
}

Answer 1

您可以使用AJAX将表单数据提交到PHP脚本。 在这种情况下，您可以将验证或成功结果作为JSON并将其付诸实践。