将原型注入单例（java配置+注释）

Question

我在采访中被问到有关将单体原型注入单例的问题。 我很难回答，现在我正在尝试对此进行研究。

我写了以下代码（启动时启动）

豆1：

@Service
@Scope(value = "prototype")
public class MyValidator {
}

豆2：

@Service
public class ValidatorHolder {

    @Autowired
    MyValidator myValidator;

    public MyValidator getMyValidator() {
        return myValidator;
    }
}

组态：

@SpringBootApplication
@Configuration
@ComponentScan("com.example.domain")
public class DemoApplication {


    public static void main(String[] args) {
        SpringApplication.run(DemoApplication.class, args);
        ApplicationContext context = new AnnotationConfigApplicationContext(DemoApplication.class);
        ValidatorHolder validatorHolder1 = (ValidatorHolder) context.getBean("validatorHolder");
        ValidatorHolder validatorHolder2 = (ValidatorHolder) context.getBean("validatorHolder");
        System.out.println("=====================================");
        System.out.println(validatorHolder1.getMyValidator() == validatorHolder2.getMyValidator());
        System.out.println("=====================================");

    }
}

该代码为true。

据我了解，在阅读文章链接时 ，可以配置为返回false。

如何在我的代码中执行？ （没有xml）

聚苯乙烯

我试图像文章中那样重写代码：

   <bean id="validatorHolder" class="com.example.domain.ValidatorHolder">
        <property name="myValidator" ref="validator"/>
    </bean>

    <bean id="validator" scope="prototype" class="com.example.domain.MyValidator">
        <!-- This instructs the container to proxy the current bean-->
        <aop:scoped-proxy/>
    </bean>

在main方法内部，我编写了以下代码：

ApplicationContext xmlContext = new FileSystemXmlApplicationContext("classpath:applicationContext.xml");
ValidatorHolder validatorHolder21 = (ValidatorHolder) xmlContext.getBean("validatorHolder");
ValidatorHolder validatorHolder22 = (ValidatorHolder) xmlContext.getBean("validatorHolder");
System.out.println("=====================================");
System.out.println(validatorHolder21.getMyValidator() == validatorHolder22.getMyValidator());
System.out.println("=====================================");

无论如何我都认为是true

PS2

让我们重新研究Sean Patrick Floyd的答案（范围代理，b））

我使用以下主要方法类：

@SpringBootApplication
@ComponentScan("com.example.domain")
public class DemoApplication {


    public static void main(String[] args) {
        SpringApplication.run(DemoApplication.class, args);

        ApplicationContext context = new AnnotationConfigApplicationContext(DemoApplication.class);
        ValidatorHolder validatorHolder1 = (ValidatorHolder) context.getBean("validatorHolder");
        ValidatorHolder validatorHolder2 = (ValidatorHolder) context.getBean("validatorHolder");
        System.out.println("=====================================");
        System.out.println(validatorHolder1.getMyValidator() == validatorHolder2.getMyValidator());
        System.out.println("=====================================");         
}

当我运行应用程序时-我看到了

org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'validatorHolder' defined in file [D:\freelance\demo\target\classes\com\example\domain\ValidatorHolder.class]: Instantiation of bean failed; nested exception is org.springframework.beans.BeanInstantiationException: Failed to instantiate [com.example.domain.ValidatorHolder]: No default constructor found; nested exception is java.lang.NoSuchMethodException: com.example.domain.ValidatorHolder.<init>()
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.instantiateBean(AbstractAutowireCapableBeanFactory.java:1099)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBeanInstance(AbstractAutowireCapableBeanFactory.java:1044)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:504)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:476)
    at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:303)
    at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230)
    at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:299)
    at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:194)
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:755)
    at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:759)
    at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:480)
    at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:689)
    at org.springframework.boot.SpringApplication.run(SpringApplication.java:321)
    at org.springframework.boot.SpringApplication.run(SpringApplication.java:969)
    at org.springframework.boot.SpringApplication.run(SpringApplication.java:958)
    at com.example.DemoApplication.main(DemoApplication.java:20)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:483)
    at com.intellij.rt.execution.application.AppMain.main(AppMain.java:134)
Caused by: org.springframework.beans.BeanInstantiationException: Failed to instantiate [com.example.domain.ValidatorHolder]: No default constructor found; nested exception is java.lang.NoSuchMethodException: com.example.domain.ValidatorHolder.<init>()
    at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:85)
    at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.instantiateBean(AbstractAutowireCapableBeanFactory.java:1092)
    ... 20 common frames omitted
Caused by: java.lang.NoSuchMethodException: com.example.domain.ValidatorHolder.<init>()
    at java.lang.Class.getConstructor0(Class.java:3074)
    at java.lang.Class.getDeclaredConstructor(Class.java:2170)
    at org.springframework.beans.factory.support.SimpleInstantiationStrategy.instantiate(SimpleInstantiationStrategy.java:80)
    ... 21 common frames omitted

PS3

PS2问题与构造函数上缺少@Autowired有关

解决此问题后

System.out.println(validatorHolder1.getMyValidator() == validatorHolder2.getMyValidator());

返回true

但是如果稍微替换一下MyValidator代码：

@Service
@Scope(value="prototype", proxyMode=ScopedProxyMode.TARGET_CLASS)
public class MyValidator {
    Object object = new Object();

    public Object getObject() {
        return object;
    }

    public void setObject(Object object) {
        this.object = object;
    }
}

---

 System.out.println(validatorHolder1.getMyValidator() == validatorHolder2.getMyValidator());

真正

 System.out.println(validatorHolder1.getMyValidator().getObject() == validatorHolder2.getMyValidator().getObject());

假

乃至

System.out.println(validatorHolder1.getMyValidator().getObject() == validatorHolder1.getMyValidator().getObject());

假

Answer 1

您误解了方法注入技术。 您需要使bean抽象才能工作：

public class MyValidator {}

public abstract class ValidatorHolder {
    public abstract MyValidator getMyValidator();
}

现在，您可以按以下方式在XML中定义bean：

<bean class="com.somepackage.MyValidator" scope="prototype" />
<bean class="com.somepackage.ValidatorHolder">
    <lookup-method name="getMyValidator" bean="myValidator" />
</bean>

在这种情况下，Spring将创建ValidatorHolder的匿名子类，该子类将在每次调用它的类型时返回原型bean（新副本）。

使用带注释的服务类，无法进行查找方法注入，但这是使用@Configuration类的方法：

@Configuration
public class MyConfiguration{

    @Bean
    @Scope("prototype")
    public MyValidator myValidator(){
        return new MyValidator();
    }

    @Bean
    public ValidatorHolder validatorHolder(){
        return new ValidatorHolder(){
            @Override public MyValidator getMyValidator(){
                return myValidator();
            }
        };
    }
}

在这种情况下，您将自己创建ValidatorHolder的子类，并且可以清楚地看到会发生什么。

但是只有当您使bean和提供者方法成为抽象时，这两个版本才有效。

最后，定义弹跳豆有三种不同的方法：

• XML格式
• 带组件扫描的带注释的类（例如@Service @Component ， @Component Component）
• 具有@Bean方法的@Configuration类。

在示例代码中，您将这三种样式混合在一起，这几乎从来不是一个好主意。 选择一种技术并坚持下去。

---

关于作用域代理，这可以通过所有三种bean注册技术来实现。

a）XML

public class MyValidator {}

public class ValidatorHolder {
    private MyValidator myValidator;
    public void setMyValidator(MyValidator myValidator){
        this.myValidator = myValidator;}
    public MyValidator getMyValidator();
}

<bean class="com.somepackage.MyValidator" scope="prototype" />
<bean class="com.somepackage.ValidatorHolder">
    <aop:scoped-proxy />
</bean>

b）带注释的服务等级

@Service @Scope(value="prototype", proxyMode=ScopedProxyMode.TARGET_CLASS)
public class MyValidator {}

@Service
public class ValidatorHolder {
    @Autowired
    public ValidatorHolder(MyValidator myValidator){
        this.myValidator=myValidator;
    }
    private final MyValidator myValidator;
    public MyValidator getMyValidator(){ return myValidator; };
}

c） @Configuration类，类似于XML版本的Bean类

@Configuration
public class MyConfiguration{

    @Bean
    @Scope("prototype")
    public MyValidator myValidator(){
        return new MyValidator();
    }

    @Bean
    public ValidatorHolder validatorHolder(){
        return new ValidatorHolder(myValidator());
    }

}

请注意，所有代理解决方案将始终返回相同的对象即代理。 但是底层功能将委托给不同的对象。 通过将以下代码添加到MyValidator来进行尝试：

private int counter = 1;
public int counter(){
    return counter ++;
}

现在，与调用此代码的频率无关：

validatorHolder.getMyValidator().counter();

它将始终返回1 。

Answer 2

@Service
public class ValidatorHolder {

@Autowired
ApplicatioContext context;

public MyValidator getMyValidator() {
    return context.getBean(MyValidator.class);
}
}

另请阅读http://shekhargulati.com/tag/method-injection/