将字符串数组转换为整数数组 Swift 2?

Question

[Xcode 7.1, iOS 9.1]

我有一个数组： var array: [String] = ["11", "43", "26", "11", "45", "40"]

我想将它（每个索引）转换成一个 Int，这样我就可以用它从一个计时器开始倒计时，对应于该索引。

如何在 Swift 2 中将String数组转换为Int数组？

我尝试了几个链接，但没有一个有效，而且所有链接都给了我一个错误。 链接中的大部分代码已贬值或尚未更新为 swift 2，例如toInt()方法。

Answer 1

使用map功能

let array = ["11", "43", "26", "11", "45", "40"]
let intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]

在像UIViewController这样的类中使用

let array = ["11", "43", "26", "11", "45", "40"]
var intArray = Array<Int>!

override func viewDidLoad() {
  super.viewDidLoad()
  intArray = array.map { Int($0)!} // [11, 43, 26, 11, 45, 40]
}

如果数组包含不同的类型，您可以使用flatMap (Swift 2) 或compactMap (Swift 4.1+) 只考虑可以转换为Int

let array = ["11", "43", "26", "Foo", "11", "45", "40"]
let intArray = array.compactMap { Int($0) } // [11, 43, 26, 11, 45, 40]

Answer 2

斯威夫特 4、5：

使用compactMap 与cast to Int，解决方案没有'!'。

let array = ["1","foo","0","bar","100"]
let arrayInt = array.compactMap { Int($0) }

print(arrayInt)
// [1, 0, 100]

Answer 3

我建议有点不同的方法

let stringarr = ["1","foo","0","bar","100"]
let res = stringarr.map{ Int($0) }.enumerate().flatMap { (i,j) -> (Int,String,Int)? in
    guard let value = j else {
        return nil
    }
    return (i, stringarr[i],value)
}
// now i have an access to (index in orig [String], String, Int) without any optionals and / or default values
print(res)
// [(0, "1", 1), (2, "0", 0), (4, "100", 100)]

Answer 4

斯威夫特 4、5：

如果您想将字符串数字转换为 int 类型的数组（在我曾经经历过的特定情况下）的即时方法：

let pinString = "123456"
let pin = pinString.map { Int(String($0))! }

对于你的问题是：

let pinArrayString = ["1","2","3","4","5","6"]
let pinArrayInt = pinArrayString.map { Int($0)! }

Answer 5

一个稍微不同的例子

let digitNames = [0: "Zero", 1: "One", 2:"Two", 3: "Three",
                  4:"Four",5:"Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine", 10:"Ten"

]

let numbers = [16,58,510]
let strings = numbers.map { (number) -> String in
    var number = number
    var output = ""
    repeat {
        output = digitNames[number % 10]! + output
        number /= 10
        
    } while number > 0
            return (output)
}

print(strings)


// strings is inferred to be of type [String]

// its value is ["OneSix", "FiveEight", "FiveOneZero"]