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[英]How do I return a field in MySQL from a sub-query linked to the main query results?
[英]How to do a subtract of 2 columns that were the results of a sub-query
我有这个查询,它按预期工作正常,即,它显示所有列以及每个子查询的2列...
SELECT
a.group_id,
a.code,
a.description_en,
c.size_code,
(
SELECT
SUM(b.qty)
FROM
receiving_details AS b
WHERE
b.code = c.size_code
) AS in_qty,
(
SELECT
SUM(d.qty)
FROM
requisition_details AS d
WHERE
d. matl_code = c.size_code
) AS out_qty
FROM products AS a
INNER JOIN products_sizes AS c ON c.prod_code = a.code
ORDER BY a.group_id ASC, a.code ASC, c.size_code ASC
但是,当我尝试添加此行时...
(in_qty - out_qty) AS balance,
在“ FROM”语句之前,我在“字段列表”中收到未知列'in_qty'的错误。
我究竟做错了什么?
编辑:
从接受的答案中,我做了一些修复,并得到了想要的结果。
SELECT *, (e.in_qty - e.out_qty) AS balance FROM
(SELECT
a.group_id,
a.code,
a.description_en,
c.size_code,
(
SELECT
IFNULL(SUM(b.qty),0)
FROM
receiving_details AS b
WHERE
b.code = c.size_code
) AS in_qty,
(
SELECT
IFNULL(SUM(d.qty),0)
FROM
requisition_details AS d
WHERE
d. matl_code = c.size_code
) AS out_qty
FROM products AS a
INNER JOIN products_sizes AS c ON c.prod_code = a.code) AS e
ORDER BY e.group_id ASC, e.code ASC, e.size_code ASC
您不能在自己的select
语句中引用相同的字段。 一种选择是将结果移动到另一个子查询中,然后执行计算:
select *, (in_qty - out_qty) AS balance
from (
SELECT
a.group_id,
a.code,
a.description_en,
c.size_code,
(
SELECT
SUM(b.qty)
FROM
receiving_details AS b
WHERE
b.code = c.size_code
) AS in_qty,
(
SELECT
SUM(d.qty)
FROM
requisition_details AS d
WHERE
d. matl_code = c.size_code
) AS out_qty
FROM products AS a
INNER JOIN products_sizes AS c ON c.prod_code = a.code
) t
ORDER BY group_id, code, size_code
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