[英]How to run a function inside a function if a condition is met
请我一直在尝试创建一个函数,该函数将查询数据库,从表中选择,如果行数不等于6,则从表中选择一行并重复(或重复)直到行数为等于6。我已经在StackOverflow中搜索了此函数,但是没有找到任何结果。 如果您有与此类似的链接,请在此处发布,我会尝试一下。
这是我的代码:
//List All active adverts
function showActiveAdverts()
{
$status = 1;
//Build final queries.
$query = mysql_query("SELECT * FROM table WHERE
status = '".mysql_real_escape_string($status)."' ORDER BY rand() LIMIT 6") or die(mysql_error());
$count = mysql_num_rows($query);
$row = mysql_fetch_assoc($query);
# My question here, check if the $count >= 1 && $count != 6, then do getDefaultBannner() and repeat it until it runs for 6 times.
if($count >= 1){
do{
$list[] = $row['id'];
}while($row = mysql_fetch_assoc($query));
return $list;
}
else{ return FALSE; }
}
这是getDefaultBannner()的代码
function getDefaultBannner()
{
$status = 6;
$query = mysql_query("SELECT id FROM table WHERE status = '".mysql_real_escape_string($status)."' ")
or die(mysql_error());
$count = mysql_num_rows($query);
$row = mysql_fetch_assoc($query);
if($count >= 1){
do{
$list[] = $row['id'];
}while($row = mysql_fetch_assoc($query));
return $list;
}
else{ return FALSE; }
}
提前致谢!
您可以这样重写代码
//List All active adverts
$query = mysql_query("SELECT * FROM table WHERE
status = '".mysql_real_escape_string($status)."' ORDER BY rand() LIMIT 6") or die(mysql_error());
$count = mysql_num_rows($query);
if($count >= 1 && $count != 6)
$list = getDefaultBannner();
else
$list = showActiveAdverts($query);
function showActiveAdverts($query)
{
$status = 1;
//Build final queries.
$row = mysql_fetch_assoc($query);
if($count >= 1){
do{
$list[] = $row['id'];
}while($row = mysql_fetch_assoc($query));
return $list;
}
else{ return FALSE; }
}
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