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[英]How to send array data from javascript image picker to php request
[英]How to send data from mysql in php to javascript array
的PHP:
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * from inventory_list";
$result=$conn->query($sql);
$row=array();
if ($result->num_rows > 0) {
// output data of each row
while($row=$result->fetch_assoc())
{ printf("NAME: %s ID: %s",$row['name'],$row['serialno']);
}
} else {
echo "0 results";
}
$conn->close();
}
那是我代码的php部分。 所以我需要将所有从mysql检索到的行保存到javascript全局数组中? 我怎样才能做到这一点 ?
正如其他人所建议的那样,您可以使用JSON。 如果您正在寻找一个起点,可以看看php的json_encode() http://php.net/manual/zh/function.json-encode.php
您可能还需要设置正确的标头:header('Content-Type:application / json');
试试这个,您需要一个JQuery库。
jQuery的:
$.ajax({
url: 'your_php_filename',
type: 'POST',
data: {},
success:function(result) {
console.log(result)//to check the value of result in array form
}
})
PHP:
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "mydb";
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * from inventory_list";
$result = $conn->query($sql);
$row = [];
if ($result->num_rows > 0) {
// output data of each row
while($row=$result->fetch_assoc()) {
$row = "NAME: ".$row['name']."ID: ".$row['serialno'];
}
} else {
echo "0 results";
}
$conn->close();
}
?>
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