这个java代码编译了，但是是错误的。 你能告诉我它有什么问题吗？

Question

这是代码，如下。 我真的需要这方面的帮助，因为我不知道它有什么问题。 正如我所说，它编译得很干净，但是每当我运行它时，它都无法执行。 谢谢！

import java.util.Scanner;
public class whatThe
{
    public static void main(String[ ] args){

     Scanner scan = new Scanner(System.in);

     int i;
     String s;
     char c;

     System.out.print("Please enter a number: ");
     i = scan.nextInt( );
     System.out.println(i);
     System.out.println( );

     System.out.print("Please input three words separated by spaces: ");
     s = scan.next();
     System.out.println(s);
     System.out.println( );

     System.out.print("Please input something:  ");
     s = scan.nextLine();
     System.out.println(s);
     System.out.println( );

     System.out.print("Please enter another number: ");
     i = scan.nextInt( );
     System.out.println(i);
     System.out.println( );

     System.out.print("Please input a word: ");
     s = scan.nextLine();
     c = s.charAt(0);
     System.out.println(c);
     System.out.println( );

     System.out.println("Good bye");

    }
}

Answer 1

package javaapplication9;
import java.util.Scanner;
import java.io.BufferedInputStream;
public class dumb
{
     public static void main(String[ ] args){

         Scanner scan = new Scanner(System.in);

         int i;
         String s;
         char result;        


         System.out.print("Please enter a number: ");
         i = scan.nextInt( );
         System.out.println(i);
         System.out.println( );

         System.out.print("Please input three words separated by spaces: ");
         s = scan.next();
         System.out.println(s);
         scan.next();


         System.out.print("Please input something:  ");
         scan.nextLine();
         s = scan.nextLine();
         System.out.println(s);
         System.out.println( );

         System.out.print("Please enter another number: ");
         i = scan.nextInt( );
         System.out.println(i);
         System.out.println( );

         System.out.print("Please input a word: ");
         scan.nextLine();
         s = scan.nextLine();
         result = s.charAt(0);
         System.out.println(result);

         System.out.println( );

         System.out.println("Good bye");

        }
    }

Answer 2

尝试这个：

    Scanner scan = new Scanner(System.in);
int i;
String s;
char c;
System.out.print("Please enter a number: ");
i = scan.nextInt( );
scan.nextLine();
System.out.println(i);
System.out.println( );

System.out.print("Please input three words separated by spaces: ");
s = scan.nextLine();

System.out.println(s);
System.out.println( );

System.out.print("Please input something:  ");
s = scan.nextLine();
System.out.println(s);
System.out.println( );

System.out.print("Please enter another number: ");
i = scan.nextInt( );
scan.nextLine();
System.out.println(i);
System.out.println( );

System.out.print("Please input a word: ");
s = scan.nextLine();
c = s.charAt(0);
System.out.println(c);
System.out.println( );

System.out.println("Good bye");

因此，在每次 scan.nextInt() 之后，执行 scan.nextLine() 以便您可以继续。