在Oracle中添加序列列

Question

我有一张桌子：TENDERINFO。 有列OrderNo，Tender，TenderSequence

我需要从1开始更新TenderSequence，然后继续直到OrderNo中的订单项数量。

我该如何实现？

Answer 1

因此，我们将按OrderNo对行进行“分组”编号。 我不知道Tender或TenderSequence是否可以充当数据的排序列，所以我只使用OrderNo。 这显示了使用窗口函数row_number（）获取行号：

select 
   OrderNo, Tender, TenderSequence,
   row_number() over (partition by OrderNo order by OrderNo asc ) rownumber,
   TenderSequence + row_number() over (partition by OrderNo order by OrderNo asc ) TS_RowNum_ADD
from
   TENDERINFO

Answer 2

WITH cte as (
   SELECT OrderNo,
          Tender,
          ROW_NUMBER() OVER ( ORDER BY OrderNo ) as rn,
          ROW_NUMBER() OVER ( PARTITION BY OrderNo ORDER BY OrderNo ) as rn2
    FROM TENDERINFO
   ) 
UPDATE TENDERINFO T
SET TenderSequence = (SELECT c.rn
                      FROM cte c
                      WHERE c.OrderNo = T.OrderNo
                        AND c.Tender = T.Tender
                     )

不知道您需要哪个row_number。

您的问题尚不清楚，每个OrderNo是否可以有多个Tender

在这种情况下，您可以使用

OVER ( ORDER BY OrderNo, Tender )

要么

OVER ( ORDER BY OrderNo, TenderSequence )

Answer 3

如果您只是尝试按顺序设置表，则从最小的OrderNo的1开始到number_of_rows到最大的OrderNo的序列，可以通过以下查询来实现：

merge into tenderinfo t 
  using (
    select 
        orderno, 
        rownum rn 
      from (select orderno from TENDERINFO order by orderno)
  ) seq on (seq.orderno = t.orderno )
  when matched then
  update set t.tendersequence = seq.rn ;