如何将流转换为BitmapImage

Question

这是我的代码

 private async void OnGetImage(object sender, RoutedEventArgs e)
        {
            using (HttpClient client = new HttpClient())
            {
                try
                {
                    HttpResponseMessage response = await client.GetAsync(new Uri(txtUri.Text));

                    BitmapImage bitmap = new BitmapImage();

                    if (response != null && response.StatusCode == HttpStatusCode.OK)
                    {

                        using (InMemoryRandomAccessStream stream = new InMemoryRandomAccessStream())
                        {
                            await response.Content.WriteToStreamAsync(stream);
                            stream.Seek(0UL);
                            bitmap.SetSource(stream);
                        }
                        this.img.Source = bitmap;
                    }
                }
                catch (Exception)
                {

                    throw;
                }
            }
        } 

但是现在我无法在uwp中使用WriteToStreamAsync（），谁可以帮助我？

Answer 1

在UWP中，可以使用HttpContent.ReadAsStreamAsync方法获取Stream ，然后将Stream转换为IRandomAccessStream以在BitmapImage使用它。 您可以尝试如下操作：

private async void OnGetImage(object sender, RoutedEventArgs e)
{
    using (HttpClient client = new HttpClient())
    {
        try
        {
            HttpResponseMessage response = await client.GetAsync(new Uri(txtUri.Text));

            BitmapImage bitmap = new BitmapImage();

            if (response != null && response.StatusCode == HttpStatusCode.OK)
            {
                using (var stream = await response.Content.ReadAsStreamAsync())
                {
                    using (var memStream = new MemoryStream())
                    {
                        await stream.CopyToAsync(memStream);
                        memStream.Position = 0;

                        bitmap.SetSource(memStream.AsRandomAccessStream());
                    }
                }
                this.img.Source = bitmap;
            }
        }
        catch (Exception)
        {
            throw;
        }
    }
}

此外， BitmapImage具有UriSource属性，您可以使用此属性获取在线图像。

bitmap.UriSource = new Uri(txtUri.Text);