内部服务器错误500 Codeigniter上载到虚拟主机

Question

我在以下网站fabcoders.com/ghostwriter上面临服务器500错误

• 以用户名登录：chelsea密码：Chelsea123
• 登录后，您将被定向到http://fabcoders.com/ghostwriter/dashboard页面。
• 在这里，您会找到一个列表作为主题，提交，查看，然后单击查看链接。
• 您将被定向到http://fabcoders.com/ghostwriter/project/view_submission/230页面，单击视图。 那就是我得到500错误。 它显示为空白，但是一旦您检查了元素并转到控制台，您就可以看到错误。

代码在codeigniter中这是控制器部分

public function view_submission_detail ($submission_id)
    {   
        $user_id = $this->session->userdata("id");
        $this->load->model("submission_m");
        $this->load->model("ratings_m");

        $star = $this->input->post("rating");
        $review=$this->input->post("reviews");
        $tip=$this->input->post("tip");


    $record  = $this->submission_m->get($submission_id);
    $rat_to=$record->fk_user_id;
    //dump($record);
    $select = $this->ratings_m->get($rat_to);
    //$tip=$select->tip;


    $this->load->model("addproject_m");
    $temp = $this->user_m->get($rat_to);


    $emailid = $temp->email;
    $user_id = $temp->id;
    $prjct = $this->addproject_m->get($record->fk_project_id); 
    //dump($record->fk_project_id);
    //dump($prjct);
    $pname = $prjct->p_title;
    $buyername = $prjct->p_buyname;
    $this->data['tip'] = $tip;
    $this->data['numele'] = count($this->submission_m->viewusersub($user_id));
    $this->data['numacc'] = count($this->submission_m->viewuseracc($user_id));
    $this->data['numrej'] = count($this->submission_m->viewuserreject($user_id));
    $this->data['numrew'] = count($this->submission_m->viewuserrewrite($user_id));
    //$this->data['usersubs'] = $this->submission_m->viewusersub($user_id);

    $get_rating_count=$this->submission_m->get_rating_count($rat_to);//rating_m
    $this->data['get_rating_count']=$get_rating_count;

    $get_rating_details=$this->submission_m->get_rating_details($rat_to);//rating_m
    $this->data['get_rating_details']=$get_rating_details;
    $sum=0;
    foreach($get_rating_details as $rows)
    {
    $sum=$sum+$rows->rating;
    }
    $average_rating=0;
    if($get_rating_count != 0)
    $average_rating=(int)($sum/$get_rating_count);

    if($this->input->post("accept") && $this->input->post("pk_submission_id")){
         redirect('dashboard');

    }else if($this->input->post("reject") && $this->input->post("pk_submission_id")){
        $this->submission_m->reject_submission($submission_id);
        $this->submission_m->rejectMail($emailid,$pname,$buyername);                    
        redirect('dashboard');

    }else if($this->input->post("rewrite") && $this->input->post("pk_submission_id")){
        $this->submission_m->rewrite_submission($submission_id);
        $this->submission_m->rewriteMail($emailid,$pname,$buyername);   
        redirect('dashboard');
    }
    $this->data['average_rating']=$average_rating;
    $this->data['submission'] =  $this->submission_m->get($submission_id);
    $this->data['username'] = $this->user_m->get($this->data['submission']->fk_user_id);
    $this->data['project'] =  $this->addproject_m->get($this->data['submission']->fk_project_id);
    $this->load->view('project/view_submission_details', $this->data);
}

这是视图部分p_title？> img / close.png“>作家的名字：

名？>

提交日期：

创建）））; ？>

评分：

  </li><?php if($tip!= ""){?> <li class="label-list">Tip for Writer:</li> <li><?php echo $tip; } ?></li> <br> <?php if($numele>=1) echo "Previous submissions";?> <br> <?php if($numele>=1) echo "Number of submissions ".$numele;?> <br> <?php if($numacc>=1) echo "Number of Projects Accepted ".$numacc;?> <br> <?php if($numrej>=1) echo "Number of Projects Rejected ".$numrej;?> <br> <?php if($numrew>=1) echo "Number of Projects Rewritten ".$numrew;?> <br> <? } ?> <?php //echo "Tip".$get_rating_details->tip ?> </ul> <div class="content1 div-center2 colorwhite"> <p class="text-content"><?php echo nl2br( htmlentities($submission->content)) ?></p> </div> <div class="buttons"> <ul class="button-row"> <?php if(!($project->p_complete==1) && ($submission->status=='NOT REVIEWED')) { ?> <?php echo form_open('','id="contentForm"'); echo form_hidden("pk_submission_id",$submission->pk_submission_id); echo " ".form_submit("accept","Accept",'class="btn-green .btn-small" id="acceptBtn"'); echo " ".form_submit("reject","Reject",'class="btn-red .btn-small"'); echo " ".form_submit("rewrite","Rewrite",'class="btn-blue .btn-small"'); echo form_close(); ?> <?php } ?> </ul> </body> </html> <script> $(function() { $("#acceptBtn").click(function(e){ var sdata = $('#contentForm').serialize(); $.ajax({ url: "<?php echo site_url('project/accept_submission'); ?>", type: "POST", data:sdata +'&accept=1', success: function(data){ $('.buttons').remove(); $('#baseModal-xs .modal-content').html(data); $('#baseModal-xs').modal("show"); } }); return false; }); }); </script> 

• 它在本地运行，但是当项目仍处于开发阶段时就无法运行。
• 我对服务器的了解不多，因为我只进行编码，但是在我的公司中，我被告知要解决此问题，但我不知道我的周末将被破坏:(
• 我之前曾发布过有关同一问题的信息，但即使没有解决，它也适用于其他部分。
• 我不知道模型部分是否也会引起问题，但是我不能放代码原因我已经超过了问题的大小

Answer 1

在视图部分，我添加了一个额外的关闭括号，其中没有打开括号，因此我删除了该括号，Wa-lah起作用了:)。