[英]What's wrong with my showChar method? Simple program intro to methods
“我应该使用一种方法来显示用户输入的单词的某个字母。
我需要使用showChar。 我确实看不到任何明显的错误,并且已经解决了两个小时。
import javax.swing.JOptionPane;
public class Ch5a {
public static void main(String[] args){
String inputString = JOptionPane.showInputDialog("What word would you like to analyze?");
String inputNumberString = JOptionPane.showInputDialog("What letter would you like to see? (Eg: For the second letter of 'dog', input 2)");
int inputNo;
inputNo = Integer.parseInt(inputNumberString);
/**
At this point, i have an input number from the user(inputNo) and I have a word from the user(inputString).
I then print the inputNo for testing.
*/
System.out.println(inputNo);
//time to call the method.
char answer;
//I declare the character answer.
answer = showChar(inputString, inputNo);
//i set it equal to the result of the method.
System.out.println("The " + inputString +" number character in " + inputNo + " is" + answer);
}
public static char showChar(String inputString, int inputNo){
//local variable
char result;
result = showChar(inputString, inputNo); //user's chosen character
//returning whatever i want in place of the method call(in this case, "result")
return result;
}
}
我想你想要这样的东西:
public static char showChar(String inputString, int inputNo){
char result;
result = inputString.charAt(inputNo -1); // since index starts at 0
return result;
}
看一下String.charAt()
方法。 我认为您想要更多类似的东西:
public static char showChar(String inputString, int inputNo){
char result;
result = inputString.charAt(inputNo - 1);
return result;
}
或简化:
public static char showChar(String inputString, int inputNo){
return inputString.charAt(inputNo - 1);
}
有关更多信息,请参见http://www.tutorialspoint.com/java/java_string_charat.htm
public static char showChar(String inputString, int inputNo){
inputNo = inputNo-1; // first letter in String has position 0
if(inputNo<0 || inputNo>=inputString.length())
{
// if the number is out of Bounds
return ' ';
}
return inputString.charAt(inputNo);
}
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