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[英]how to delete data from database in php,ajax,javascript(no jquery)
[英]Delete data from database using PHP & JavaScript
我正在处理PHP文件。 我正在尝试制作一个表,该表显示数据库中的产品列表。 还有一个用于删除任何产品的按钮。 我已使用JavaScript从数据库中删除产品。 我已经编写了代码,找不到任何错误。 当我单击删除按钮时,它向我显示确认框,但不删除产品。 这是代码:
<?php
$con=mysql_connect("localhost","root","");
mysql_select_db("grocery_shop",$con);
error_reporting(E_ALL^E_NOTICE);
session_start();
$sql = mysql_query("select * from products");
if($_GET['did']){
mysql_query("delete from products where product_id='$_GET[did]'");
header("Location: product.php");
}
?>
<table border="1px" style="width:100%">
<tr>
<th>Serial No</th>
<th>Product Name</th>
<th>Product Type</th>
<th>Quantity</th>
<th>Price</th>
<th>Delete Product</th>
</tr>
<tr>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<?php
$i=1;
while ($u = mysql_fetch_array($sql)) {
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $u['product_name'];?></td>
<td><?php echo $u['product_type'];?></td>
<td><?php echo $u['quantity'];?></td>
<td><?php echo $u['price'];?></td>
<td><?php echo "<a href=\"javascript:delproduct(id=$u[product_id])\">Delete</a>";?></td>
</tr>
<?php
$i++;
}
?>
<script>
function delproduct(id){
var msg = confirm("Are you sure you want to delete this product?");
if (msg) {
window.location = "product.php?did="+product_id;
}
}
</script>
</table>
您忘记了$ _GET [did]中的“”操作:
mysql_query("delete from products where product_id='{$_GET['did']}'");
另外,正如@ chris85所指出的那样,直接使用$ _GET或$ _POST不是一个好主意,记住在查询中使用它们之前要清理掉这些值。
$did = filter_input(INPUT_GET, 'did', FILTER_SANITIZE_NUMBER_INT);
mysql_query("delete from products where product_id={$did}");
问题出在您的JavaScript中,product_id不存在
if (msg) {
window.location = "product.php?did="+id;
}
为了进行调试,请尝试用您的代码替换它,并让我们知道您收到的错误消息。
if($_GET['did']){
mysql_query("delete from products where product_id='".$_GET['did']."'");
echo "delete from products where product_id='".$_GET['did']."'";
echo mysql_errno() . ": " . mysql_error() ;
die();
//header("Location: product.php");
}
另外还要尝试在不使用单引号的情况下运行查询,我假设product_id是整数。
因此, mysql_query("delete from products where product_id=".$_GET['did']);
您应该尝试: delproduct($ u [product_id])而不是delproduct(id = $ u [product_id])
mysql_query("delete from products where product_id='".$_GET['did']."'");
while ($u = mysql_fetch_array($sql)) {
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $u['product_name'];?></td>
<td><?php echo $u['product_type'];?></td>
<td><?php echo $u['quantity'];?></td>
<td><?php echo $u['price'];?></td>
<td><?php echo "<a href=\"javascript:delproduct($u[product_id])\">Delete</a>";?></td>
</tr>
<?php
$i++;
}
<?php
$con=mysql_connect("localhost","root","");
mysql_select_db("grocery_shop",$con);
error_reporting(E_ALL^E_NOTICE);
session_start();
$sql = mysql_query("select * from products");
if($_GET['did']){
mysql_query("delete from products where product_id='$_GET[did]'");
header("Location: product.php");
}
?>
<table border="1px" style="width:100%">
<tr>
<th>Serial No</th>
<th>Product Name</th>
<th>Product Type</th>
<th>Quantity</th>
<th>Price</th>
<th>Delete Product</th>
</tr>
<tr>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
<td></td>
</tr>
<?php
$i=1;
while ($u = mysql_fetch_array($sql)) {
?>
<tr>
<td><?php echo $i; ?></td>
<td><?php echo $u['product_name'];?></td>
<td><?php echo $u['product_type'];?></td>
<td><?php echo $u['quantity'];?></td>
<td><?php echo $u['price'];?></td>
<td><?php echo "<a href=\"javascript:delproduct(".$u[product_id].")\">Delete</a>";?></td>
</tr>
<?php
$i++;
}
?>
<script>
function delproduct(id){
var product_id = id;
var msg = confirm("Are you sure you want to delete this product?");
if (msg) {
window.location = "product.php?did="+product_id;
}
}
</script>
</table>
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