如何在PHP中浏览JSON数组中的每个元素

Question

我想要回显出JSON数组的对象的每个元素，如下所示：

{"request_list":[{"id":"1","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null},{"id":"3","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null}]}

但我不能这样做。我尝试过这样的事情：

$object = json_decode($json, true);
$request_list = $object->request_list;
foreach($request_list as $r){
    echo $r->name;
    echo $r->blood_type;
    echo $r->phone_number;
}

但我得到一个错误：

为foreach（）提供的参数无效

Answer 1

因为你在json_decode标记返回为数组true。 所以，试试下面的代码。

 $object = json_decode($json, true);
 $request_list = $object['request_list'];
 foreach($request_list as $r){
    echo $r['name'];
    echo $r['blood_type'];
    echo $r['phone_number'];
}

Answer 2

用这个

$object = json_decode($json, true);
$request_list = $object['request_list'];
foreach($request_list as $r){
    echo $r['name'];
    echo $r['blood_type'];
    echo $r['phone_number'];
}

Answer 3

尝试

    $json = '{"request_list":[{"id":"1","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null},{"id":"3","name":"yunus","surname":"smsk","phone_number":"05350601922","blood_type":"0","unit_of_blood":"0","date":null}]}';
    $data = json_decode($json );

    $request = $data->request_list;

    foreach($request as $request_data){
        echo $request_data->id;
        echo $request_data->name;
        echo $request_data->surname;
    }