Drupal 7 | 迁移：如何将分类标签按名称关联到节点？

Question

我一直在尝试设置我的迁移模块一段时间，但未成功将分类学术语与节点相关联。

首先要说的是，它不是 D2D迁移，来源是旧的symfony数据库！

首先，我成功导出了分类法术语：

* - migrate.inc：

...
  'symfony_db_countries' => array(
    'class_name' => 'MigrateSymfonyCountriesMigration',
    'group_name' => 'symfony_db_loc',
  ),
  'symfony_db_cities' => array(
    'class_name' => 'MigrateSymfonyCitiesMigration',
    'group_name' => 'symfony_db_loc',
    'dependencies' => array('symfony_db_countries'),
  ),    
  'symfony_db_sights' => array(
    'class_name' => 'MigrateSymfonySightsMigration',
    'group_name' => 'symfony_db_loc',
  ),
...

Cities.inc：

class MigrateSymfonyCitiesMigration extends MigrateSymfonyCitiesMigrationBase {

  const TABLE_NAME = 'ya_loc_city';

  public function __construct($arguments = array()) {
    parent::__construct($arguments);

    $this->description = t('Migrate cities from Symfony DB.');

    $query = Database::getConnection('symfony', 'default')->select('ya_loc_city', 'c');
    $query->leftJoin('ya_loc_city_translation', 'ct', 'ct.id = c.id');
    $query->fields('c', array());
    $query->fields('ct', array());

    $this->source = new MigrateSourceSQL($query, array(), NULL, array('map_joinable' => FALSE));

    $this->destination = new MigrateDestinationTerm('cities');

    $this->map = new MigrateSQLMap($this->machineName,
        array(
          'id' => array(
            'type' => 'int',
            'not null' => TRUE,
            'description' => 'City ID',
          ),
        ),
        MigrateDestinationTerm::getKeySchema()
    );

    $this->addFieldMapping('name', 'name');
    $this->addFieldMapping('parent', 'country_id')->sourceMigration('symfony_db_countries');
  }
} 

然后，Im从另一个表创建节点，该表具有分类术语的entityReference字段（field_city）。

<?php
class MigrateSymfonySightsMigration extends Migration {
  public function prepareRow($row) {
    parent::prepareRow($row);
    $row->point = 'point (' . $row->longitude . ' ' . $row->latitude. ')';
  }

  public function __construct($arguments = array()) {
    //entry is the name of a group.
    parent::__construct($arguments);
    $this->description = 'Migration sights';

    /*************SOURCE DATA*************/
    ... 

    $this->source = new MigrateSourceSQL($query, array(), NULL,
      array('map_joinable' => FALSE));

    $this->destination = new MigrateDestinationNode('sight');

    /*************MAPPING*************/

    $this->addFieldMapping('field_city', 'name')->sourceMigration('symfony_db_cities');

    $this->map = new MigrateSQLMap($this->machineName,
       array(
         'id' => array('type' => 'int',
                            'unsigned' => TRUE,
                            'not null' => TRUE,
                      )
       ),
       MigrateDestinationNode::getKeySchema()
    );
  }
}

在symfony表中，有一列“名称”，其中包含城市名称，如“巴黎”。

如何将此列（“ 名称 ”）值（“ 巴黎 ”）与分类术语相关联？ 以下不起作用：

$this->addFieldMapping('field_city', 'name')->sourceMigration('symfony_db_cities');

Answer 1

首先，请确保您的“ field_city”字段接受“ cities”字词。

然后确保MigrateSymfonyCitiesMigration是MigrateSymfonySightsMigration的依赖项。

根据文档 ，术语参考字段迁移默认情况下具有术语名称的“ source_type”。 确保正确设置了“ ignore_case”。

如果其他所有方法均失败，则将MigrateSymfonyCitiesMigration映射源ID1更改为“名称”，而不是“ id”，然后重试（必须重新注册迁移）：

$this->map = new MigrateSQLMap($this->machineName,
    array(
      'name' => array(
        'type' => 'varchar',
        'length' => 255,
        'not null' => TRUE,
        'description' => 'City Name',
      ),
    ),
    MigrateDestinationTerm::getKeySchema()
);