[英]Downgrade PDO SQL to mysql_query
我正在使用mysql_语句的旧脚本上工作。 每当我尝试发出任何mysqli_或PDO语句时,一切都会变得很棘手。 因此,我需要重写以下代码,以便它与我正在重新编程的脚本一起使用。
$ids = $_POST['delete'];
$params = array_fill(0, count($ids), "?");
$sql = "DELETE FROM some_table WHERE id IN (" . implode(",", $params) . ")";
$pdo = new PDO('mysql:host=localhost;dbname=mydb', 'user', 'pass');
$stmt = $pdo->prepare($sql);
$stmt->execute($ids);
我正在使用的代码中的常规连接看起来更像:
include "inc/config.php";
include "inc/funcs.php";
@mysql_connect($dbhost,$dbuser,$dbpass);
@mysql_select_db($dbname) or die( "Unable to select database");
include "inc/userauth.php";
if ($_POST && isset($_POST['value'])) {
$value = mysql_real_escape_string($_POST['value']);
$sql = "UPDATE oto_members SET right_sidebar = '".$value."' WHERE username='".$_SESSION['uid']."'";
mysql_query($sql);
}
那么,我将如何重新编写PDO代码,使其与旧的mysql_样式调用一起使用?
错误,将您的第一个示例代码-/-pdo复制/粘贴到第二个示例中?
include "inc/config.php";
include "inc/funcs.php";
@mysql_connect($dbhost,$dbuser,$dbpass);
@mysql_select_db($dbname) or die( "Unable to select database");
include "inc/userauth.php";
if ($_POST && isset($_POST['value'])) {
$value = mysql_real_escape_string($_POST['value']);
$ids = $_POST['delete'];
$params = array_fill(0, count($ids), "?");
$sql = "DELETE FROM some_table WHERE id IN (" . implode(",", $params) . ")";
mysql_query($sql);
}
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