[英]codeigniter active record 'inner' join
query('SELECT * FROM answers INNER JOIN questions
WHERE answers.answerId= questions.questionId AND answers.answerId IN (' . $id . ')')
我需要帮助将其更改为活动记录的codeigniter。
我试图从两个表中获取等于id的值并将其加入。 但是当我尝试这样
$this->db->select("*"); $this->db->join("questions","questions.questionId = answers.answerId"); $this->db->where_in('answers.answerId',$id); $res = $this->db->get("answers");
它仅显示通过id传递的第一个联接表。
尝试这个
$this->db->select('*');
$this->db->from('answers');
$this->db->join('questions','questions.questionId=answers.answerId');
$this->db->where_in('answers.answerId',$id);
$query=$this->db->get();
$result=$query->result();
默认情况下,其内部联接
$this->db->select("*");
$this->db->join("questions","questions.questionId = answers.answerId");
$this->db->where_in('answers.answerId',$id);
$res = $this->db->get("answers");
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