jQuery split（）返回未定义

Question

我有problam idont知道为什么蝙蝠我在所有“ field_input”中都看到“ undefined”

当我尝试从jquery .split添加时

 function field_include() { var form_id = $( ".form" ).val(); $.ajax({ url: 'ajax/field_include.php', type: 'POST', data: { form_id : form_id }, success: function(data) { var fields = data; var field = fields.split(";").filter(Boolean); $.each(field, function(i, val){ var field_val = val.split(","); $( ".addfromform" ).append('<div class="form-group"><label class="col-lg-2 control-label mt10">'+field_val[2]+'</label><div class="col-xs-10"><label for="'+field_val[1]+'" class="field prepend-icon"><input type="'+field_val[0]+'" name="'+field_val[1]+'" id="first_name" class="gui-input" placeholder="'+field_val[3]+'" autocomplete="off"><label for="'+field_val[1]+'" class="field-icon"><i class="fa fa-user"></i></label></label></div></div>').fadeIn('slow'); }); } }); } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script> 

来自“ field_include.php”的字符串：

1,first_name,First Name:,First Name,1;1,last_name,Last Name:,Last Name,2;1,email,Email:,Email,3;1,job,Job title:,Job title,4;

我该如何解决？

Answer 1

尝试将.filter(Boolean)链接到.filter(Boolean) fields.split(";")以删除field最后一个索引处的空字符串"" ，其中字符串的最后一个索引处的字符为";" 它将在var field_input = val.split(',');处返回undefined 如val将为空字符串""

var field = fields.split(";").filter(Boolean);

---

 var fields = "1,first_name,First Name:,First Name,1;1,last_name,Last Name:,Last Name,2;1,email,Email:,Email,3;1,job,Job title:,Job title,4;"; var field1 = fields.split(";"); var field2 = fields.split(";").filter(Boolean); $.each(field2, function(i, val) { var field_val = val.split(","); $("body").append('<div class="form-group"><label class="col-lg-2 control-label mt10">' + field_val[2] + '</label><div class="col-xs-10"><label for="' + field_val[1] + '" class="field prepend-icon"><input type="' + field_val[0] + '" name="' + field_val[1] + '" id="first_name" class="gui-input" placeholder="' + field_val[3] + '" autocomplete="off"><label for="' + field_val[1] + '" class="field-icon"><i class="fa fa-user"></i></label></label></div></div>'); }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>