[英]Passing variables from one class to an other in PhP
您好,我正在尝试使用lorna jane mitchell博客中的说明构建我的第一个Restful Web服务和即时消息。
如果要求通过此网址: http:// localhost:8888 / lorna / index.php / tree / getpath?node_id = 75我将调用getpath函数传递给node_id,该函数get path如下所示:
class NestedSet
{
public function getPath($id) {
$sql = "SELECT p." . $this->pk . ", p." . $this->name . " FROM ". $this->table . " n, " . $this->table . " p WHERE n.lft BETWEEN p.lft AND p.rgt AND n." . $this->pk ." = " . $id . " ORDER BY p.lft;";
$result = $this->db->query($sql);
if ($result->num_rows == 0) {
return $this->error(1, true);
}
$path = array();
$i = 0;
while ($row = $result->fetch_assoc()) {
$path[$i] = $row;
$i++;
}
return $path;
}
}
现在,我想将此变量$ path传递给看起来像这样的类JsonView:
class JsonView extends ApiView {
public function render($path) {
header('Content-Type: application/json; charset=utf8');
echo json_encode($path);
return true;
}
}
class ApiView {
protected function addCount($data) {
if(!empty($data)) {
// do nothing, this is added earlier
} else {
$data['meta']['count'] = 0;
}
return $data;
}
}
关于如何通过此JsonView类传递变量$ path或任何其他变量的任何想法。 非常感谢您的宝贵时间 :)
UPDATE这是用于创建嵌套类对象的代码
public function getAction($request) {
$data = $request->parameters;
if(isset($request->url_elements[2])) {
switch ($request->url_elements[2]) {
case 'getpath':
$id = $data['node_id'];
$nested = new NestedSet();
$nested->getPath($id);
$api = new JsonView();
$api->render($path);
break;
default:
# code...
break;
}
} else {
$nested = new NestedSet();
echo $nested->treeAsHtml();
}
}
只需创建JsonView的对象,然后使用该对象调用函数render。
$api = new JsonView;
$api->render($path);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.