如何在XSLT 2.0中引用分组元素？

Question

我想对以下XML文件进行分组：

<record>
    <word>Hallo</word><translit>XUPPY</translit><gloss>gloss1</gloss>
    <word>Bye</word><translit>EHS</translit><gloss>gloss2</gloss>
    <word>Yes</word><translit>KGR</translit><gloss>gloss3</gloss>
</record>

所需的输出是

<s>
    <set><word>Hallo</word><gloss>gloss1</gloss></set>
    <set><word>Bye</word><gloss>gloss2</gloss></set>
    <set><word>Yes</word><gloss>gloss3</gloss></set>
</s>

所以我使用for-each-group ，如

<xsl:template match="record">
    <xsl:element name="s">
        <xsl:for-each-group select="*" group-starting-with="word">
            <xsl:element name = "set">
                <xsl:copy-of select="current-group()/word"/>
                <xsl:copy-of select="current-group()/gloss"/>
            </xsl:element>
        </xsl:for-each-group>
    </xsl:element>
</xsl:template>

但是，我得到以下输出，即空组：

<s><set/><set/><set/></s> 

所以我在引用组中的元素时做错了。 但是呢 我相信这一定很简单。

Answer 1

word和gloss是当前组的成员 ，而不是其子级。

尝试：

<xsl:template match="/record">
    <s>
        <xsl:for-each-group select="*" group-starting-with="word">
            <set>
                <xsl:copy-of select="current-group()[self::word or self::gloss]"/>
            </set>
        </xsl:for-each-group>
    </s>
</xsl:template>

Answer 2

current-group()为您提供current-group()所有元素，如果要选择某个元素，请使用current-group()[self::gloss] 。

我会取代

        <xsl:element name = "set">
            <xsl:copy-of select="current-group()/word"/>
            <xsl:copy-of select="current-group()/gloss"/>
        </xsl:element>

与

<set>
  <xsl:copy-of select="., current-group()[self::gloss]"/>
</set>