从PHP中的XML提取

Question

<toplevel>
 <CompleteSuggestion>
  <suggestion data="shook ones part 2"/>
 </CompleteSuggestion>
 <CompleteSuggestion>
  <suggestion data="shook me all night long"/>
 </CompleteSuggestion>
 <CompleteSuggestion>
  <suggestion data="shook ones instrumental"/>
 </CompleteSuggestion>
 <CompleteSuggestion>
  <suggestion data="shook me all night long lyrics"/>
 </CompleteSuggestion>
</toplevel>

我想从此XML输出中提取“第2部分”。 我已经解决了所有解决方案，但无法做到这一点。 我尝试了这个：

<?php
$url = 'http://suggestqueries.google.com/complete/search?output=toolbar&hl=en&q=shook&ds=yt';
$exact = simplexml_load_file($url);
echo $exact->CompleteSuggestion[0]->suggestion;
?>

Answer 1

shook ones part 2是一个属性的值data的suggestion 。 因此，您应该使用功能attributes()获得suggestion所有属性，然后选择data ：

$exact = simplexml_load_file('$url');
echo $exact->CompleteSuggestion[0]->suggestion->attributes()->data;

Answer 2

省略单引号

simplexml_load_file('$url');
                    ^    ^

Answer 3

您可以为此使用DOMDocumen t。 以下示例将搜索标签建议并回显data属性：

$domDocument = new DOMDocument();
$domDocument->loadXML( $xml );

$value = $domDocument->getElementsByTagName( "suggestion" );
foreach ( $value as $e ) {
    echo $e->getAttribute( "data" )."<br>";
}