使用php解析数据并将值插入mysql数据库？

Question

php代码检查json数据是否来自android代码。

<?php
require "init.php";
if($_POST){
 print_r($_POST);
}else{
 echo "Nothing came from android code";
}
?>

作为响应，我正在获取json数据，如下所示：

（[jsonarray] => [{“ custInfo”：“ Ujwal 9975022560”，“ rate”：“ 24000”，“ weight”：“ 21.00000”，“ desc”：“ GENTS ANGTHI 22k NO STONE”，“ makingAmt”：“ 200“，” sum_total“：” RS.156283.38“，” vat“：” RS.3064.38“，” itemTotal“：” 51073“，”条形码“：” BQSP78BB“，” net_rate“：” 24200“，” date“ ：:“ 2015-12-02”，“发票编号”：“ 1”，“ bill_type”：“发票”}，{“ custInfo”：“ Ujwal 9975022560”，“ rate”：“ 24000”，“ weight”：“ 21.00000 “，” desc“：” GENTS ANGTHI 22k NO STONE“，” makingAmt“：” 200“，” sum_total“：” RS.156283.38“，” vat“：” RS.3064.38“，” itemTotal“：” 51073“， “条形码”：“ BQSP78BB”，“ net_rate”：“ 24200”，“日期”：“ 2015-12-02”，“发票编号”：“ 1”，“帐单类型”：“发票”}，{“ custInfo”： “ Ujwal 9975022560”，“ rate”：“ 24000”，“ weight”：“ 21.00000”，“ desc”：“ GENTS ANGTHI 22k NO STONE”，“ makingAmt”：“ 200”，“ sum_total”：“ RS.156283.38” ，“ vat”：“ RS.3064.38”，“ itemTotal”：“ 51073”，“条形码”：“ BQSP78BB”，“ net_rate”：“ 24200”，“ date”：“ 2015-12-02”，“ invoiceNo” ：“ 1”，“ bill_type”：“发票”}]）

我想做的就是解析此响应并将数据插入到mysql数据库中。

foreach ( $data as $inv ) {
    $custInfo = $inv->custInfo;
    $rate =     $inv->rate;
    $weight=    $inv->weight;
    $desc=      $inv->desc;
    $makingAmt= $inv->makingAmt;
    $vat=       $inv->vat;
    $itemTotal= $inv->itemTotal;
    $sum_total= $inv->sum_total;
    $barcode=   $inv->barcode;
    $net_rate=  $inv->net_rate;
    $date=      $inv->date;
    $invoiceNo= $inv->invoiceNo;
    $bill_type= $inv->bill_type;
    $sql = "INSERT INTO selected_items 
             (custInfo, invoiceNo, barcode, desc, 
              weight, rate, makingAmt,net_rate,
              itemTotal,vat,sum_total,bill_type,date) 
            VALUES
             ('$custInfo','$invoiceNo','$barcode','$desc',
              '$weight','$rate','$makingAmt','$net_rate',
              '$itemTotal','$vat','$sum_total','$bill_type','$date')";
    $res = mysqli_query($sql,$con);

我是php新手，所以尝试了json_decode，但它返回一个空字符串作为响应。 我如何解析custInfo, invoiceNo, barcode, desc,weight, rate, makingAmt,net_rate,itemTotal,vat,sum_total,bill_type,date到我的表selected_items.

谢谢你:)

Answer 1

试试这个（更新）：

$arr = json_decode(stripslashes($_POST['jsonarray']), true);
$env = $arr['jsonarray'];

Answer 2

$myArray = json_decode($data, true);


 $sql = "INSERT INTO selected_items 
             (custInfo, invoiceNo, barcode) 
            VALUES
             ('$myArray['custInfo'],$myArray['invoiceNo'],$myArray['barcode'])";
    $res = mysqli_query($sql,$con);

Answer 3

编辑：添加了一些错误检查，以帮助调试代码。

您可以尝试使用json_decode将其直接解码为数组

那么您可以使用extract（）将 变量从数组导入当前符号表中，从而消除了foreach循环。

<?php
    require "init.php";
    if($_POST){
        $data = $_POST;
        $array = json_decode($data, true);

        if($array===NULL){return print_r('json decode failed!');}
        if(!is_array($array)){return print_r('Well, the decoded data is corrupt, its supposed to be an array, '.gettype($array).' given!');}

        if(!isset($array['jsonarray'])){return print_r('no json data was ever received!');}
        extract($array['jsonarray']);

        $sql = "INSERT INTO selected_items 
         (custInfo, invoiceNo, barcode, desc, 
          weight, rate, makingAmt,net_rate,
          itemTotal,vat,sum_total,bill_type,date) 
        VALUES
         ('$custInfo','$invoiceNo','$barcode','$desc',
          '$weight','$rate','$makingAmt','$net_rate',
          '$itemTotal','$vat','$sum_total','$bill_type','$date')";
$res = mysqli_query($sql,$con);

    }else{
        echo "Nothing came from android code";
    }
?>