[英]Static variable concatenating the previous result value php
我具有此递归函数,可将所有中间类别从第n个孩子获取到父类别。 但是,当id更改时,变量$ cats将串联到前一个结果。 在执行第二个第n个子ID之前,我不希望它为null。 见下面的代码
function find_parent($cat_id,$conn){
static $cats;
if ($cat_id > 0){
$q = mysqli_query($conn,'SELECT pw_cat_pid FROM pw_categories WHERE pw_cat_id = ' . $cat_id) or die(mysqli_error($conn));
$r = mysqli_fetch_assoc($q);
$cats[] = $cat_id;
find_parent($r["pw_cat_pid"],$conn);
}
return $cats;
}
$sub_cat = array(5,122);
foreach($sub_cat as $value)
{
$cat = find_parent($value);
print_r($cat);
}
It showed below result:
If $sub_cat = 5
Array ( [0] => 5 [1] => 3 [2] => 1 )
If $sub_cat = 122
Array ( [0] => 5 [1] => 3 [2] => 1 [3] => 121 [4] => 97 [5] => 1 )
不要使用静态变量,请使用by-refrence实现目标:
function find_parent($cat_id,$conn, &$cats=array()){
if ($cat_id > 0){
$q = mysqli_query($conn,'SELECT pw_cat_pid FROM pw_categories WHERE pw_cat_id = ' . $cat_id) or die(mysqli_error($conn));
$r = mysqli_fetch_assoc($q);
$cats[] = $cat_id;
find_parent($r["pw_cat_pid"],$conn,$cats);
}
return $cats;
}
$sub_cat = array(5,122);
foreach($sub_cat as $value)
{
$cat = find_parent($value,$conn);
echo "<pre>";
print_r($cat);
}
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