[英]oracle SQL : getting DEPT by min and max sums
我有2个工作子查询,用于检查所有部门中的最小和最大SUMS(DEPTNO)。 表EMP和DEPT具有DEPTNO单元格
(SELECT min(sum(e.SAL)) FROM EMP e GROUP by e.DEPTNO);
(SELECT max(sum(e.SAL)) FROM EMP e GROUP by e.DEPTNO);
如何检查最小和最大子查询的DEPTNO? 我的代码有错误:
SELECT d.DEPTNO
FROM DEPT d
WHERE sum(e.SAL) = (SELECT max(sum(e.SAL)) FROM EMP e GROUP by d.DEPTNO);
如果您希望部门获得最大的总和,则可以使用rownum
或row_number()
:
select ed.*
from (select e.deptno, sum(e.sal) as sums,
row_number() over (order by sum(e.sal) desc) as seqnum
from emp e
group by e.deptno
) ed
where seqnum = 1;
在Oracle 12g +中,也可以写成:
select e.deptno, sum(e.sal) as sums,
row_number() over (order by sum(e.sal) desc) as seqnum
from emp e
group by e.deptno
order by sum(e.sal) desc
fetch first 1 row only;
这是使用cte
一种方法
with salsums as (select deptno, sum(sal) salsum from emp group by deptno)
, maxandmin as (select max(salsum) maxsal, min(salsum) minsal from salsums)
select deptno
from salsums cross join maxandmin
where salsum = maxsal or salsum = minsal
好的,这比开始时要难。 这就是我最终使它工作的方式,但是我更喜欢@vkp的答案。
with sums as
(
SELECT DEPTNO, SUM(SAL) AS SSAL
FROM EMP
GROUP BY DEPTNO
), mm as
(
SELECT DEPTNO, SSAL, MIN(SSAL) OVER () as MIN_SSAL, MAX(SSAL) OVER () as MAX_SSAL
FROM SUMS
)
SELECT 'MIN', DEPTNO, SSAL FROM mm WHERE SSAL=MIN_SSAL
UNION ALL
SELECT 'MAX', DEPTNO, SSAL FROM mm WHERE SSAL=MAX_SSAL
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.