[英]Extracting a key-value pair from inside a string
我有以下字符串:
string myString = "{'gridObject':'[1,2,3,4],[5,6,7,8]'}";
如何将其处理为对象,以便可以执行以下操作:
charts[0] //=> [1,2,3,4]
charts[0][1] //=> 2
如果我可以将其转换为该对象,那就更好了:
public class gridObject {
public int datarow {get; set;}
public int datacol {get; set;}
public int datasizex {get; set;}
public int datasizey {get; set;}
}
这就是我要做的。
首先创建您的课程,
public class GridObject
{
public int datarow { get; set; }
public int datacol { get; set; }
public int datasizex { get; set; }
public int datasizey { get; set; }
}
public class GridObjectCollection
{
public GridObject[] GridObjects { get; set; }
}
然后,查看所需的JSON,将其序列化一次:( JsonConvert是Json.NET的一部分,您可以使用NuGet来获取它)
GridObjectCollection gridObjects = new GridObjectCollection();
gridObjects.GridObjects = new GridObject[]
{
new GridObject() { datacol = 1, datarow = 2, datasizex = 3, datasizey = 4 },
new GridObject() { datacol = 5, datarow = 6, datasizex = 7, datasizey = 8 }
};
Console.WriteLine
(
JsonConvert.SerializeObject
(
gridObjects,
new JsonSerializerSettings() { Formatting = Formatting.Indented }
)
);
在这里,您可以看到反序列化时将生成这些类的有效JSON内容如下:
{
"GridObjects": [
{
"datarow": 2,
"datacol": 1,
"datasizex": 3,
"datasizey": 4
},
{
"datarow": 6,
"datacol": 5,
"datasizex": 7,
"datasizey": 8
}
]
}
然后,只需尝试反序列化即可确保:
var f = JsonConvert.DeserializeObject<GridObjectCollection>
(
"{'GridObjects':[{'datarow':2,'datacol':1,'datasizex':3,'datasizey':4},{'datarow':6,'datacol':5,'datasizex':7,'datasizey':8}]}"
);
这是一种实现方法:
public static gridObject[] Parse(string str)
{
int first = str.IndexOf("[");
int last = str.LastIndexOf("]");
str = str.Substring(first, last - first + 1);
string[] big_parts = str.Split(new string[] {"[", "],[", "]"} , StringSplitOptions.RemoveEmptyEntries);
return big_parts.Select(x =>
{
string[] small_parts = x.Split(',');
return new gridObject()
{
datarow = Convert.ToInt32(small_parts[0]),
datacol = Convert.ToInt32(small_parts[1]),
datasizex = Convert.ToInt32(small_parts[2]),
datasizey = Convert.ToInt32(small_parts[3]),
};
}).ToArray();
}
它首先搜索第一个[
和最后一个]
并修剪[
和之后]
之前的所有内容。
然后,它基于[
, ],[
, ]
分割字符串。
您的示例将得到1,2,3,4
和5,6,7,8
。
然后,对于其中的每一个,我们基于进行拆分,
然后将结果转换为gridObject
对象。
使用自定义解析完成:
public class GridObject
{
public int datarow { get; set; }
public int datacol { get; set; }
public int datasizex { get; set; }
public int datasizey { get; set; }
}
/// <summary>
/// MySuperObject class which holds a reference to inner array of integers
/// </summary>
public class MySuperObject
{
public List<int> Items { get; set; } // Inner array of list of integers
public MySuperObject()
{
Items = new List<int>();
}
public override string ToString()
{
// Need to override ToString to return something like "[1,2,3,4]"
var result = "";
foreach (var item in Items)
{
if (result.Length > 0)
result += ",";
result += item.ToString();
}
return string.Format("[{0}]", result);
}
/// <summary>
/// Function to generate GridObject from existing set of integers
/// </summary>
public GridObject GetGridObject()
{
var result = new GridObject();
if (Items.Count >= 1) result.datarow = Items[0];
if (Items.Count >= 2) result.datacol = Items[1];
if (Items.Count >= 3) result.datasizex = Items[2];
if (Items.Count >= 4) result.datasizey = Items[3];
return result;
}
}
// Parse functions
public List<MySuperObject> Parse(string value)
{
if (string.IsNullOrEmpty(value))
throw new ArgumentException("value cannot be null or empty!", "value");
var result = new List<MySuperObject>();
// First get the indexes of first [ and last ]
var idxStart = value.IndexOf("[");
var idxEnd = value.LastIndexOf("]");
// Check validity
if (idxStart < 0 || idxEnd < 0 || idxEnd <= idxStart)
return result; // Return empty list
value = value.Substring(idxStart, idxEnd - idxStart + 1).Trim();
// Split by [] after replacing spaces with empty strings (and removing first and last [ and ])
var arr = value.Replace(" ", "").Trim('[',']').Split(new[] { "],[" }, StringSplitOptions.RemoveEmptyEntries);
foreach (var str in arr)
{
// Construct list of integers with a help of LINQ
var nums = str.Split(',').Select(t => Convert.ToInt32(t)).ToList();
// Create and add MySuperObject to existing list which will be returned
result.Add(new MySuperObject
{
Items = new List<int>(nums),
});
}
return result;
}
这是这种解析的用法:
var myString = "{'gridObject':'[1,2,3,4],[5,6,7,8]'}";
var value = Parse(myString);
// Get all grid objects
var allGridObjects = value.Select(t => t.GetGridObject()).ToList();
当然,这可能需要更多的错误检查,但基本上,此MySuperObject可用于使用任意数量的所需整数,同时为您提供“ GetGridObject”的辅助方法,以用数组中的适当数字填充网格对象数字。
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