[英]Visual Studio (2015) C Project dependency - LNK1561 entry point must be defined
我在C项目中具有以下主程序,该主思想(想法)使用同一解决方案中另一个项目的标头和utils文件。 头文件包含在utils文件中的函数声明(如下所示)
主功能:
#include <stdio.h>
#include "header1C.h"
#include "utils_1C.c"
#include <stdbool.h>
int main() {
int num = 0, base = 0, rKey;
do {
bool chk = false; //flag for while loop to check if base is correct
printf("\nEnter number [Enter -1 to exit]: ");
scanf_s("%d", &num); //number to be changed
if (num != -1) {
do {
printf("Enter new base [2,4,8 or 16]: ");
scanf_s("%d", &base); //new base [2,4,8,16]
if ((base != 2) && (base != 4) && (base != 8) && (base != 16)){
printf("Number must be either 2,4,8 or 16\n");
}
else chk = true; //set flag to true
} while (chk == false);
newBase(num, base); //calls newBase() with parameters num and base
}
rKey = getchar(); //getchar to clear char buffer
if (num == -1)
printf("\n[Press any key to exit]");
rKey = getchar(); //readkey to exit programm on any key press
} while (num != -1); //to be repeated until num entered by user is -1
return 0;
}
在一个名为Library的单独项目中:
头文件header1C.h:
char checkHex(int n);
void newBase(int n, int b);
实用程序文件utils_1C.c:
#include "header1C.h"
char checkHex(int n) { //used by newBase() - converts given number to letters if larger than 9
switch (n) {
case 10: return 'A'; //return A if n = 10
case 11: return 'B'; //return B if n = 11
case 12: return 'C'; //return C if n = 12
case 13: return 'D'; //return D if n = 13
case 14: return 'E'; //return E if n = 14
case 15: return 'F'; //return F if n = 15
}
return n; //return given number if < 10
}
void newBase(int n, int b) {
static char newNum[50]; //array in which the number is stored (array of remainders)
int i = 0; //counter
do { //long division and gathering of remainder
newNum[i] = checkHex(n % b); //calling checkHex() to check number and conert to letter if needed
n = n / b; //divide n by b
i++; //counter + 1
} while (n >= b); //loop stops when n is smaller than it's divider b
newNum[i] = checkHex(n); //calling checkHex()
printf("\nNumber in base %d: ", b); //flipped number - proper answer
for (i; i >= 0; i--) { //loop stops when smaller than 0
if ((newNum[i] >= 65) && (newNum[i] <= 70)) //check if newNum[i] is a letter [A-F]
printf("%c", newNum[i]); //output if letter
else
printf("%d", newNum[i]); //output if number
}
}
我收到此错误:
错误LNK1561入口点必须定义库C:\\ Users ... \\ Assignments \\ Library \\ LINK 1
我已将Library作为项目依赖项添加到具有主要功能的项目中,并且我还尝试了
属性->配置属性->链接器->系统->子系统
以下其他答案我在堆栈溢出,但没有运气。
在这一点上,我不知道该怎么办,并且坦率地说,我不认为这将成为一个很大的问题(尽管我可能会遗漏一些东西?)
对于长期存在的问题,我们深表歉意,并提供帮助。
使用C ++编译代码时,链接器需要一个int main()
。
当您将main()
定义为返回void
,链接程序找不到程序的入口点。
与C相对,C ++确实知道函数的返回类型,函数的签名。
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