SQL从查询结果中删除重复项

Question

这是我的SQL：

 SELECT * FROM unity_database.unit_uptime_daily
        inner join unity_database.units on unity_database.units.id = unity_database.unit_uptime_daily.unit_id
        where unity_database.units.location_id = 1

以下是结果第一部分的屏幕截图：

我试图为每个具有最新日期的unit_id仅显示一个结果，因此在此示例中，unit_id为30的单位应仅显示一次，并且应该在最下面一行。

有任何想法吗？

Answer 1

WITH X AS
(
SELECT * 
       ,ROW_NUMBER() OVER (PARTITION BY Unit_Id ORDER BY [Timestamp] DESC) rn
FROM unity_database.unit_uptime_daily
inner join unity_database.units 
on unity_database.units.id = unity_database.unit_uptime_daily.unit_id
where unity_database.units.location_id = 1
)
SELECT * FROM X Where rn = 1

要么

SELECT * 
FROM (
    SELECT * 
           ,ROW_NUMBER() OVER (PARTITION BY Unit_Id ORDER BY [Timestamp] DESC) rn
    FROM unity_database.unit_uptime_daily
    inner join unity_database.units 
    on unity_database.units.id = unity_database.unit_uptime_daily.unit_id
    where unity_database.units.location_id = 1
     )A
WHERE rn = 1

Answer 2

您可以考虑以下MySQL解决方案：

SELECT t1.id, t1.unit_id, t1.uptime, t1.total_update, t2.timestamp
FROM
(
    SELECT *
    FROM unity_database.unit_uptime_daily ud1 INNER JOIN unity_database.units ud2
        ON ud2.id = ud1.unit_id
    WHERE ud2.location_id = 1
) t1
INNER JOIN
(
    SELECT ud1.unit_id, MAX(ud1.timestamp) AS timestamp
    FROM unity_database.unit_uptime_daily ud1 INNER JOIN unity_database.units ud2
        ON ud2.id = ud1.unit_id
    WHERE ud2.location_id = 1
    GROUP BY ud1.unit_id
) t2
ON t1.unit_id = t2.unit_id AND t1.timestamp = t2.timestamp

Answer 3

如果此答案能给您期望的结果，请：

 SELECT MAX(id) AS ID, unit_id, uptime, total_update, MAX(timestamp) as timesstamp FROM unity_database.unit_uptime_daily
    inner join unity_database.units on unity_database.units.id = unity_database.unit_uptime_daily.unit_id
 where unity_database.units.location_id = 1
 GROUP BY unit_id, uptime, total_update

PS：我没有测试，但是我很肯定它会起作用