如何在Codeigniter中传递数据以查看

Question

假设我有一个像这样的叫家的控制器

class Home extends CI_Controller{


    public function __construct()
    {
        parent::__construct();

        //load the settings model
        $this->load->Model('settings_model');

        //get the all settings and store it into a variable
        $siteSettings = $this->settings_model->SiteSettings();


        //how to pass the data to view
        $data['site'] = $siteSettings;
    }

    public function index()
    {
        //some code and pass the value to view
        $data["some_item"] = "some value";

        //Load the view
        $this->load->view("home",$data);
    }

    public function SomeMethod1()
    {
        //some code and pass the value to view
        $data["some_item"] = "some value";

        //Load the view
        $this->load->view("home",$data);
    }


    public function SomeMethod2()
    {
        //some code and pass the value to view
        $data["some_item"] = "some value";

        //Load the view
        $this->load->view("home",$data);
    }


}

但是我的问题是我想将$ siteSettings传递给我的每个方法。 我不想每次都使用我的家用控制器的不同方法从settings_model获取数据。 我只想从__construct（）上的数据库中获取数据，并在我调用其他方法时将值传递给每个方法。

我怎样才能做到这一点？ 我是否应该使用公共变量并将获取的数据存储到此变量，然后从其他方法调用该变量？

Answer 1

在会话中进行设置。 并可以访问整个项目。

public function __construct()
{
    parent::__construct();
    $this->session->unset_userdata('site'); # unset on each and every time

    $this->load->Model('settings_model');
    $siteSettings = $this->settings_model->SiteSettings();

    $this->session->set_userdata('site', $siteSettings);  # Set after end of __construct
}

或者像这样

public function __construct()
{
    parent::__construct();

    $this->load->Model('settings_model');
    $this->data['site']  = $this->settings_model->SiteSettings();
}

在功能上

$this->load->view("name",$this->data);