[英]SQLite SUM() between several rows
我倾向于将这个问题说成:将所有行中的数量加起来,这些行中有一个音符“前面”。 这表明:
select sum(quantity)
from (select ft.*,
(select count(*)
from fuel_table ft2
where ft2.note = 'Yes' and ft2.id >= ft.id
) as numNotesAhead
from fuel_table ft
) ft
where numNotesAhead = 1;
WITH max_id_with_note AS
(
SELECT MAX(ID) AS max_id
FROM YourTable
WHERE IFNULL(note, '') <> ''
)
, previous_max_id_with_note AS
(
SELECT max(ID) as max_id
FROM YourTable
WHERE IFNULL(note, '') <> ''
AND ID < (SELECT max_id FROM max_id_with_note)
)
SELECT SUM(Quantity)
FROM YourTable
WHERE (SELECT max_id FROM previous_max_id_with_note)
< ID and ID <=
(SELECT max_id FROM max_id_with_note)
首先选择几个ROW并从此选择查询SUM()。 在你的情况下它看起来像这样:
Select SUM(t1.QUANTITY) FROM (SELECT QUANTITY from fuel_table WHERE NOTE!='' ORDER BY ID limit 2) as t1
将您的查询更改为
SELECT Sum(QUANTITY) FROM fuel_table ORDER BY ID DESC LIMIT 3
我像你一样创建了表并进行测试。 安道尔有好主意,但犯了一些错误!
WITH max_id_with_note AS
(
SELECT MAX(ID) AS max_id
FROM fuel_table
WHERE Note <> ''
)
, previous_max_id_with_note AS
(
SELECT max(ID) as max_id
FROM fuel_table
WHERE Note <> ''
AND ID < (SELECT max_id FROM max_id_with_note)
)
SELECT SUM(Quantity)
FROM fuel_table
WHERE (SELECT max_id FROM previous_max_id_with_note)
< id and id <= (SELECT max_id FROM max_id_with_note)
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