[英]A function that shuffles an array passed as an argument
我正在学校做一个项目,我想创建一个函数来对作为参数传递的数组进行混洗。 我试图创建一个,但它没有按我预期的那样工作......
在这段代码中,我试图复制传递数组的元素并在第二个数组中以随机顺序设置它们。 然后,在传递的数组中再次复制它们..
这是源代码:
void shufarray(int* array, int b)
{
int hold[b];
int i,k;
int randV=0, randHold=0;
srand(b);
for(i=0; i<b; ++i) {
hold[rand() % (b-1)] = array[i];
k=0;
do {
if(k==0) {
randHold = randV;
k=-1;
} //end if
randV = rand()%(b-1);
} while(randHold != randV);//end of do\while stetment
hold[randV] = array[i];
} //end for
for(i=0;i<b;++i) {
array[i]=hold[i];
} //end for
} //end shufarray()
这是输出:
hold[ 0 ] = 8
hold[ 1 ] = 11
hold[ 2 ] = 2
hold[ 3 ] = 15
hold[ 4 ] = 18
hold[ 5 ] = 10
hold[ 6 ] = 11
hold[ 7 ] = 17
hold[ 8 ] = 24
hold[ 9 ] = 21
hold[ 10 ] = 12
hold[ 11 ] = 2
hold[ 12 ] = 15
hold[ 13 ] = 9
hold[ 14 ] = 13
hold[ 15 ] = 1
hold[ 16 ] = 15
hold[ 17 ] = 1
hold[ 18 ] = 22
hold[ 19 ] = 11
hold[ 20 ] = 11
hold[ 21 ] = 18
hold[ 22 ] = 17
hold[ 23 ] = 4
hold[ 24 ] = 7
shuffled_hold[ 0 ] = 7
shuffled_hold[ 1 ] = 32561
shuffled_hold[ 2 ] = 22
shuffled_hold[ 3 ] = 0
shuffled_hold[ 4 ] = 18
shuffled_hold[ 5 ] = 8
shuffled_hold[ 6 ] = -632114865
shuffled_hold[ 7 ] = 32561
shuffled_hold[ 8 ] = -628693440
shuffled_hold[ 9 ] = 11
shuffled_hold[ 10 ] = 15
shuffled_hold[ 11 ] = 18
shuffled_hold[ 12 ] = 1
shuffled_hold[ 13 ] = 13
shuffled_hold[ 14 ] = 15
shuffled_hold[ 15 ] = 12
shuffled_hold[ 16 ] = 17
shuffled_hold[ 17 ] = 0
shuffled_hold[ 18 ] = 4
shuffled_hold[ 19 ] = 17
shuffled_hold[ 20 ] = 7
shuffled_hold[ 21 ] = 0
shuffled_hold[ 22 ] = -1
shuffled_hold[ 23 ] = 0
shuffled_hold[ 24 ] = 0
所以我试图了解这个操作的原理,任何人都可以帮我找出问题所在..谢谢。
问题
在前面的代码中,我认为解决方案是创建一个数组hold[]
来保存从array[]
随机复制的元素。 比将元素从hold[]
再次复制回array[]
问题是:
hold[]
未初始化有时程序会覆盖已经覆盖的元素
srand(b) 将始终根据长度给出相同的排列
解决方案
我根据评论中建议的参考修改了代码。
正确的做法是从最后一个元素array[n-1]
,将它与从整个数组(包括最后一个)中随机选择的元素交换。 现在考虑from 0 to n-2
的数组(大小减 1),并重复该过程直到我们命中第一个元素。 详细算法如下:
for i from n - 1 downto 1 do
j = random integer with 0 <= j <= i
exchange a[j] and a[i] .
编码
void shufarray(int* array, int b){
int i,k=0;
srand(time(NULL));//set the seed
/* Starting from the last element and swap one by one.
* NOTE: i > 0 it's because there's no need to run for the first element */
for (i = b-1; i > 0; i--){
int j = rand() % (i+1);
//swap
k = array[i];
array[i] = array[j];
array[j] = k;
}//end for
}//end shufarray()
输出
hold[ 0 ] = 8
hold[ 1 ] = 11
hold[ 2 ] = 2
hold[ 3 ] = 15
hold[ 4 ] = 18
hold[ 5 ] = 10
hold[ 6 ] = 11
hold[ 7 ] = 17
hold[ 8 ] = 24
hold[ 9 ] = 21
hold[ 10 ] = 12
hold[ 11 ] = 2
hold[ 12 ] = 15
hold[ 13 ] = 9
hold[ 14 ] = 13
hold[ 15 ] = 1
hold[ 16 ] = 15
hold[ 17 ] = 1
hold[ 18 ] = 22
hold[ 19 ] = 11
hold[ 20 ] = 11
hold[ 21 ] = 18
hold[ 22 ] = 17
hold[ 23 ] = 4
hold[ 24 ] = 7
shuffled_hold[ 0 ] = 24
shuffled_hold[ 1 ] = 9
shuffled_hold[ 2 ] = 8
shuffled_hold[ 3 ] = 1
shuffled_hold[ 4 ] = 15
shuffled_hold[ 5 ] = 11
shuffled_hold[ 6 ] = 11
shuffled_hold[ 7 ] = 21
shuffled_hold[ 8 ] = 17
shuffled_hold[ 9 ] = 7
shuffled_hold[ 10 ] = 11
shuffled_hold[ 11 ] = 11
shuffled_hold[ 12 ] = 18
shuffled_hold[ 13 ] = 10
shuffled_hold[ 14 ] = 1
shuffled_hold[ 15 ] = 15
shuffled_hold[ 16 ] = 13
shuffled_hold[ 17 ] = 2
shuffled_hold[ 18 ] = 18
shuffled_hold[ 19 ] = 4
shuffled_hold[ 20 ] = 17
shuffled_hold[ 21 ] = 2
shuffled_hold[ 22 ] = 12
shuffled_hold[ 23 ] = 15
shuffled_hold[ 24 ] = 22
参考资料: Fisher-Yates shuffle
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