如何通过匹配ID将数组推入对象

Question

我要从包含currentDataResult和pastDataResult的api返回一个对象数组。

[
{
    "sectionCurrentDataResult": [
        {
            "section_id": 14785,
            "subdivision_name": "Stratton Woods",
        },
        {
            "section_id": 14790,
            "subdivision_name": "Stratton Woods",
        },
        {
            "section_id": 14791,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14792,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14781,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14786,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14787,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14788,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14782,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14783,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 14784,
            "subdivision_name": "Stratton Woods"
        },
        {
            "section_id": 5326,
            "subdivision_id": 1439,
            "subdivision_name": "Stratton Woods"
        }
    ]
},
{
    "sectionPastDataResult": [
        {
            "section_id": 5326,
            "price_min": 177,
            "price_max": 235
        },
        {
            "section_id": 14785,
            "price_min": 190,
            "price_max": 220
        },
        {
            "section_id": 14786,
            "price_min": 238,
            "price_max": 292
        },
        {
            "section_id": 14788,
            "price_min": 186,
            "price_max": 205
        },
        {
            "section_id": 14790,
            "price_min": 150,
            "price_max": 269
        },
        {
            "section_id": 14783,
            "price_min": 150,
            "price_max": 260
        },
        {
            "section_id": 14787,
            "price_min": 90,
            "price_max": 90
        },
        {
            "section_id": 14792,
            "price_min": 177,
            "price_max": 235
        },
        {
            "section_id": 14791,
            "price_min": 145,
            "price_max": 221
        },
        {
            "section_id": 14784,
            "price_min": 148,
            "price_max": 186
        },
        {
            "section_id": 14781,
            "price_min": 155,
            "price_max": 200
        },
        {
            "section_id": 14782,
            "price_min": 150,
            "price_max": 170
        }
      ]
    }
  ]

我需要将匹配的pastDataObject（by section_id）对象作为嵌套数组推入currentDataResult对象。 这就是它需要的样子

"sectionCurrentDataResult": [
        {
            "section_id": 14785,
            "subdivision_name": "Stratton Woods",
            "sectionHistory":[{
               "section_id": 14785,
               "price_min": 190,
               "price_max": 220
            }]
        },
        {
            "section_id": 14790,
            "subdivision_name": "Stratton Woods",
            "sectionHistory":[{
               "section_id": 14790,
               "price_min": 150,
               "price_max": 269
            }]
        },
        etc....
        ]

我创建了一个服务，该服务同时获取当前和过去的数据结果，并对过去的数据结果进行重新排序以匹配当前的结果。 我需要帮助的是将过去的数据数组推送到当前数据对象中。 现在它错误地将整个过去的数据数组推入第一个对象到当前数据数组。我已经用代码设置了一个插件。

plunker

app.controller('MainCtrl', function($scope,bigEnchilada,inputHistorySvc) {

   for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i++) {
        bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory =  inputHistorySvc.historyInputs(bigEnchilada);
        }
      $scope.sections = bigEnchilada[0].sectionCurrentDataResult;

    });

Answer 1

这是您要找的东西吗？

var app = angular.module('angularjs-starter', []);

app.controller('MainCtrl', function($scope,bigEnchilada,inputHistorySvc) {
var list = inputHistorySvc.historyInputs(bigEnchilada);
for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i++){
   for (var j = 0; j < list.length; j++ ) {
      if(bigEnchilada[0].sectionCurrentDataResult[i].section_id ==      list[j].section_id){
          bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory = list[j];
      }
   }
}
  $scope.sections = bigEnchilada[0].sectionCurrentDataResult;

});

输出：

[
{
"section_id": 14785,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14785,
  "price_min": 190,
  "price_max": 220
}
},
{
"section_id": 14790,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14790,
  "price_min": 150,
  "price_max": 269
}
},
 {
"section_id": 14791,
"subdivision_name": "Stratton Woods",
"sectionHistory": {
  "section_id": 14791,
  "price_min": 145,
  "price_max": 221
}
},

等等

Answer 2

var inputHistory = inputHistorySvc.historyInputs(bigEnchilada);
  for (var i = 0; i < bigEnchilada[0].sectionCurrentDataResult.length; i = i + 1) {
      for (x = 0; x < inputHistory.length; x = x + 1) {
        if (bigEnchilada[0].sectionCurrentDataResult[i].section_id === inputHistory[x].section_id) {
          bigEnchilada[0].sectionCurrentDataResult[i].sectionHistory = inputHistory[x];
        }
      }
      }
  $scope.sections = bigEnchilada[0].sectionCurrentDataResult;

Answer 3

您可以使用一个临时对象和两个单独的循环。 一种用于获取所有引用，第二种用于将数据分配给该引用。 此解决方案中的Big O ： O（n） 。

 var data = [{ "sectionCurrentDataResult": [{ "section_id": 14785, "subdivision_name": "Stratton Woods", }, { "section_id": 14790, "subdivision_name": "Stratton Woods", }, { "section_id": 14791, "subdivision_name": "Stratton Woods" }, { "section_id": 14792, "subdivision_name": "Stratton Woods" }, { "section_id": 14781, "subdivision_name": "Stratton Woods" }, { "section_id": 14786, "subdivision_name": "Stratton Woods" }, { "section_id": 14787, "subdivision_name": "Stratton Woods" }, { "section_id": 14788, "subdivision_name": "Stratton Woods" }, { "section_id": 14782, "subdivision_name": "Stratton Woods" }, { "section_id": 14783, "subdivision_name": "Stratton Woods" }, { "section_id": 14784, "subdivision_name": "Stratton Woods" }, { "section_id": 5326, "subdivision_id": 1439, "subdivision_name": "Stratton Woods" }] }, { "sectionPastDataResult": [{ "section_id": 5326, "price_min": 177, "price_max": 235 }, { "section_id": 14785, "price_min": 190, "price_max": 220 }, { "section_id": 14786, "price_min": 238, "price_max": 292 }, { "section_id": 14788, "price_min": 186, "price_max": 205 }, { "section_id": 14790, "price_min": 150, "price_max": 269 }, { "section_id": 14783, "price_min": 150, "price_max": 260 }, { "section_id": 14787, "price_min": 90, "price_max": 90 }, { "section_id": 14792, "price_min": 177, "price_max": 235 }, { "section_id": 14791, "price_min": 145, "price_max": 221 }, { "section_id": 14784, "price_min": 148, "price_max": 186 }, { "section_id": 14781, "price_min": 155, "price_max": 200 }, { "section_id": 14782, "price_min": 150, "price_max": 170 }] }]; void function () { var o = {}; data[0].sectionCurrentDataResult.forEach(function (a) { o[a.section_id] = a; }); data[1].sectionPastDataResult.forEach(function (a) { o[a.section_id].sectionHistory = [a]; }); }(); document.write('<pre>' + JSON.stringify(data, 0, 4) + '</pre>'); 

Answer 4

如果破坏此json，实际上可以避免嵌套循环，请按section_id对其进行排序，然后仅在单个循环中创建所需的对象。 您还可以避免if -else循环和equality check

     // Get sorted array of  sectionCurrentDataResult
var array1 = a[0]["sectionCurrentDataResult"].sort(function(x,y){
     return x.section_id>y.section_id? 1 : x.section_id<y.section_id? -1 :0; 
  })

 // Get sorted array of  sectionPastDataResult

var array2= a[1]["sectionPastDataResult"].sort(function(x,y){
     return x.section_id>y.section_id? 1 : x.section_id<y.section_id? -1 :0; 
  })

// Will be populated with merged data
var sectionCurrentDataResult=[]

  for(var a = 0;a<array1.length;a++){
      var sectionHistory=[];
      sectionHistory.push({
      "section_id":array2[a].section_id,
      "price_min":array2[a].price_min,
      "price_max":array2[a].price_max
      })
      sectionCurrentDataResult.push({
      "section_id":array1[a].section_id,
      "subdivision_name":array1[a].subdivision_name,
      "sectionHistory":sectionHistory
      })
  }
  console.log(sectionCurrentDataResult);

工作实例