ASP.Net Web APi C＃-GetAsync不返回XML响应内容

Question

我正在使用GetAsync()调用外部服务，并在查询字符串中传递参数。 当我检查响应中的内容时，我看不到任何返回的内容，但是它返回200 OK并且在提琴手中它正确地向我返回了XML响应。 我需要XML响应才能反序列化为C＃对象，然后将其进一步保存到DB。

尝试过的事情：

1）通过在global- app_start（）中添加此设置进行了尝试，这没有帮助

GlobalConfiguration.Configuration.Formatters.XmlFormatter.UseXmlSerializer = true;

2）创建了一个对象，并尝试通过GetAysnc发送该GetAysnc ，但也没有帮助。

public class Request
    {
        [XmlElement]
        public string XML { get; set; }
        [XmlElement]
        public List<string> ProNumber { get; set; }
    }

2）我应该尝试在查询字符串中传递参数并期望json结果吗？ 如果我将mediatyperformatter添加到application/json ？

这是我的代码：

public async Task<HttpResponseMessage> GetData()
{
    string requestString = "&xml=Y&PRONumber=82040X,03117X";
    string result = "";

    string url = @"http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController";
    try
    {
        using (var client = new HttpClient())
        {
            client.BaseAddress = new Uri(url);
            client.DefaultRequestHeaders.Accept.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/xml"));

            HttpResponseMessage response = await client.GetAsync(url+requestString);

            if (response.IsSuccessStatusCode)
            {
                return response;
            }
        }
    }
    catch (Exception ex)
    {
        result = ex.Message;
    }
    return null;
}

编辑：

                        Shipments scp = null;
                        XmlRootAttribute xRoot = new XmlRootAttribute();
                        xRoot.ElementName = "Shipment";
                        xRoot.IsNullable = true;
                        XmlSerializer serializer = new XmlSerializer(typeof(Shipment), xRoot);

                    using (Stream stream = response.Content.ReadAsStreamAsync().Result)
                    {
                        scp = (Shipments)serializer.Deserialize(stream);
                    }

模型：

public class Shipments
    {
        [XmlArrayItem(Type = typeof(Shipment))]
        public Shipment[] Shipment;
    }

    public class Shipment
    {
        [XmlAttribute()]
        public int returnCode { get; set; }
        .................
        ..............

收到错误消息： <SHIPMENTS xmlns=''> was not expected. 发生 <SHIPMENTS xmlns=''> was not expected.

任何帮助对此表示感谢。

谢谢，WH

Answer 1

这对我有用-

var client = new HttpClient();
var data = client.GetStringAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;
var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(new StringReader(data));


public class Shipment
{
    public string returnCode { get; set; }
    public string returnMessage { get; set; }
    public string freightBillNumber { get; set; }
    //props
}

[XmlRoot(ElementName = "SHIPMENTS")]
public class Shipments
{
    [XmlElement(ElementName = "SHIPMENT")]
    public List<Shipment> SHIPMENT { get; set; }
}

编辑

这也很好-

var data = client.GetStreamAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;

编辑

效果很好-

var client = new HttpClient();
var data = client.GetAsync("http://my.yrc.com/dynamic/national/servlet?CONTROLLER=com.rdwy.ec.rextracking.http.controller.PublicTrailerHistoryAPIController&xml=Y&PRONumber=82040X,03117X").Result;

var ser = new XmlSerializer(typeof(Shipments));
var t = (Shipments)ser.Deserialize(data.Content.ReadAsStreamAsync().Result);