将通用列表/枚举转换为数据表？

Question

我有几个方法可以返回不同的通用列表。

.net 中是否存在任何类静态方法或将任何列表转换为数据表的任何方法？ 我唯一能想象的就是使用反射来做到这一点。

如果我有这个：

List<Whatever> whatever = new List<Whatever>();

（下一个代码当然不起作用，但我希望有以下可能性：

DataTable dt = (DataTable) whatever;

Answer 1

这是使用来自 NuGet 的FastMember 的2013 年更新：

IEnumerable<SomeType> data = ...
DataTable table = new DataTable();
using(var reader = ObjectReader.Create(data)) {
    table.Load(reader);
}

这使用 FastMember 的元编程 API 以获得最大性能。 如果您想将其限制为特定成员（或强制执行命令），那么您也可以这样做：

IEnumerable<SomeType> data = ...
DataTable table = new DataTable();
using(var reader = ObjectReader.Create(data, "Id", "Name", "Description")) {
    table.Load(reader);
}

编辑派息/索赔：FastMember是马克Gravell项目。 它是金色的，而且是苍蝇！

---

是的，这几乎是完全相反的这一个; 反射就足够了 - 或者如果你需要更快，2.0 中的HyperDescriptor ，或者 3.5 中的Expression 。 实际上， HyperDescriptor应该HyperDescriptor 。

例如：

// remove "this" if not on C# 3.0 / .NET 3.5
public static DataTable ToDataTable<T>(this IList<T> data)
{
    PropertyDescriptorCollection props =
        TypeDescriptor.GetProperties(typeof(T));
    DataTable table = new DataTable();
    for(int i = 0 ; i < props.Count ; i++)
    {
        PropertyDescriptor prop = props[i];
        table.Columns.Add(prop.Name, prop.PropertyType);
    }
    object[] values = new object[props.Count];
    foreach (T item in data)
    {
        for (int i = 0; i < values.Length; i++)
        {
            values[i] = props[i].GetValue(item);
        }
        table.Rows.Add(values);
    }
    return table;        
}

现在，通过一行，您可以使其比反射快许多倍（通过为对象类型T启用HyperDescriptor ）。

---

编辑重新性能查询； 这是一个带有结果的测试台：

Vanilla 27179
Hyper   6997

我怀疑瓶颈已经从成员访问转移到DataTable性能......我怀疑你会在这方面有所改进......

代码：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Diagnostics;
public class MyData
{
    public int A { get; set; }
    public string B { get; set; }
    public DateTime C { get; set; }
    public decimal D { get; set; }
    public string E { get; set; }
    public int F { get; set; }
}

static class Program
{
    static void RunTest(List<MyData> data, string caption)
    {
        GC.Collect(GC.MaxGeneration, GCCollectionMode.Forced);
        GC.WaitForPendingFinalizers();
        GC.WaitForFullGCComplete();
        Stopwatch watch = Stopwatch.StartNew();
        for (int i = 0; i < 500; i++)
        {
            data.ToDataTable();
        }
        watch.Stop();
        Console.WriteLine(caption + "\t" + watch.ElapsedMilliseconds);
    }
    static void Main()
    {
        List<MyData> foos = new List<MyData>();
        for (int i = 0 ; i < 5000 ; i++ ){
            foos.Add(new MyData
            { // just gibberish...
                A = i,
                B = i.ToString(),
                C = DateTime.Now.AddSeconds(i),
                D = i,
                E = "hello",
                F = i * 2
            });
        }
        RunTest(foos, "Vanilla");
        Hyper.ComponentModel.HyperTypeDescriptionProvider.Add(
            typeof(MyData));
        RunTest(foos, "Hyper");
        Console.ReadLine(); // return to exit        
    }
}

Answer 2

我不得不修改 Marc Gravell 的示例代码来处理可空类型和空值。 我在下面包含了一个工作版本。 谢谢马克。

public static DataTable ToDataTable<T>(this IList<T> data)
{
    PropertyDescriptorCollection properties = 
        TypeDescriptor.GetProperties(typeof(T));
    DataTable table = new DataTable();
    foreach (PropertyDescriptor prop in properties)
        table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
    foreach (T item in data)
    {
        DataRow row = table.NewRow();
        foreach (PropertyDescriptor prop in properties)
             row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
        table.Rows.Add(row);
    }
    return table;
}

Answer 3

对Marc 的答案进行了一个小改动，使其适用于List<string>类的值类型到数据表：

public static DataTable ListToDataTable<T>(IList<T> data)
{
    DataTable table = new DataTable();

    //special handling for value types and string
    if (typeof(T).IsValueType || typeof(T).Equals(typeof(string)))
    {

        DataColumn dc = new DataColumn("Value", typeof(T));
        table.Columns.Add(dc);
        foreach (T item in data)
        {
            DataRow dr = table.NewRow();
            dr[0] = item;
            table.Rows.Add(dr);
        }
    }
    else
    {
        PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(typeof(T));
        foreach (PropertyDescriptor prop in properties)
        {
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
        }
        foreach (T item in data)
        {
            DataRow row = table.NewRow();
            foreach (PropertyDescriptor prop in properties)
            {
                try
                {
                    row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
                }
                catch (Exception ex)
                {
                    row[prop.Name] = DBNull.Value;
                }
            }
            table.Rows.Add(row);
        }
    }
    return table;
}

Answer 4

这是解决方案的简单组合。 它适用于 Nullable 类型。

public static DataTable ToDataTable<T>(this IList<T> list)
{
  PropertyDescriptorCollection props = TypeDescriptor.GetProperties(typeof(T));
  DataTable table = new DataTable();
  for (int i = 0; i < props.Count; i++)
  {
    PropertyDescriptor prop = props[i];
    table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
  }
  object[] values = new object[props.Count];
  foreach (T item in list)
  {
    for (int i = 0; i < values.Length; i++)
      values[i] = props[i].GetValue(item) ?? DBNull.Value;
    table.Rows.Add(values);
  }
  return table;
}

Answer 5

另一种方法是上面的：

  List<WhateEver> lst = getdata();
  string json = Newtonsoft.Json.JsonConvert.SerializeObject(lst);
  DataTable pDt = JsonConvert.DeserializeObject<DataTable>(json);

Answer 6

MSDN 上的这个链接值得一看： How to: Implement CopyToDataTable<T> Where the Generic Type T Is Not a DataRow

这添加了一个扩展方法，让您可以执行此操作：

// Create a sequence. 
Item[] items = new Item[] 
{ new Book{Id = 1, Price = 13.50, Genre = "Comedy", Author = "Gustavo Achong"}, 
  new Book{Id = 2, Price = 8.50, Genre = "Drama", Author = "Jessie Zeng"},
  new Movie{Id = 1, Price = 22.99, Genre = "Comedy", Director = "Marissa Barnes"},
  new Movie{Id = 1, Price = 13.40, Genre = "Action", Director = "Emmanuel Fernandez"}};

// Query for items with price greater than 9.99.
var query = from i in items
             where i.Price > 9.99
             orderby i.Price
             select i;

// Load the query results into new DataTable.
DataTable table = query.CopyToDataTable();

Answer 7

public DataTable ConvertToDataTable<T>(IList<T> data)
{
    PropertyDescriptorCollection properties =
        TypeDescriptor.GetProperties(typeof(T));

    DataTable table = new DataTable();

    foreach (PropertyDescriptor prop in properties)
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);

    foreach (T item in data)
    {
        DataRow row = table.NewRow();
        foreach (PropertyDescriptor prop in properties)
        {
           row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
        }
        table.Rows.Add(row);
    }
    return table;
}

Answer 8

It's also possible through XmlSerialization.
The idea is - serialize to `XML` and then `readXml` method of `DataSet`.

I use this code (from an answer in SO, forgot where)

        public static string SerializeXml<T>(T value) where T : class
    {
        if (value == null)
        {
            return null;
        }

        XmlSerializer serializer = new XmlSerializer(typeof(T));

        XmlWriterSettings settings = new XmlWriterSettings();

        settings.Encoding = new UnicodeEncoding(false, false);
        settings.Indent = false;
        settings.OmitXmlDeclaration = false;
        // no BOM in a .NET string

        using (StringWriter textWriter = new StringWriter())
        {
            using (XmlWriter xmlWriter = XmlWriter.Create(textWriter, settings))
            {
               serializer.Serialize(xmlWriter, value);
            }
            return textWriter.ToString();
        }
    }

so then it's as simple as:

            string xmlString = Utility.SerializeXml(trans.InnerList);

        DataSet ds = new DataSet("New_DataSet");
        using (XmlReader reader = XmlReader.Create(new StringReader(xmlString)))
        { 
            ds.Locale = System.Threading.Thread.CurrentThread.CurrentCulture;
            ds.ReadXml(reader); 
        }

Not sure how it stands against all the other answers to this post, but it's also a possibility.

Answer 9

尝试这个

public static DataTable ListToDataTable<T>(IList<T> lst)
{

    currentDT = CreateTable<T>();

    Type entType = typeof(T);

    PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(entType);
    foreach (T item in lst)
    {
        DataRow row = currentDT.NewRow();
        foreach (PropertyDescriptor prop in properties)
        {

            if (prop.PropertyType == typeof(Nullable<decimal>) || prop.PropertyType == typeof(Nullable<int>) || prop.PropertyType == typeof(Nullable<Int64>))
            {
                if (prop.GetValue(item) == null)
                    row[prop.Name] = 0;
                else
                    row[prop.Name] = prop.GetValue(item);
            }
            else
                row[prop.Name] = prop.GetValue(item);                    

        }
        currentDT.Rows.Add(row);
    }

    return currentDT;
}

public static DataTable CreateTable<T>()
{
    Type entType = typeof(T);
    DataTable tbl = new DataTable(DTName);
    PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(entType);
    foreach (PropertyDescriptor prop in properties)
    {
        if (prop.PropertyType == typeof(Nullable<decimal>))
             tbl.Columns.Add(prop.Name, typeof(decimal));
        else if (prop.PropertyType == typeof(Nullable<int>))
            tbl.Columns.Add(prop.Name, typeof(int));
        else if (prop.PropertyType == typeof(Nullable<Int64>))
            tbl.Columns.Add(prop.Name, typeof(Int64));
        else
             tbl.Columns.Add(prop.Name, prop.PropertyType);
    }
    return tbl;
}

Answer 10

Marc Gravell 的回答但在 VB.NET 中

Public Shared Function ToDataTable(Of T)(data As IList(Of T)) As DataTable
    Dim props As PropertyDescriptorCollection = TypeDescriptor.GetProperties(GetType(T))
    Dim table As New DataTable()
    For i As Integer = 0 To props.Count - 1
            Dim prop As PropertyDescriptor = props(i)
            table.Columns.Add(prop.Name, prop.PropertyType)
    Next
    Dim values As Object() = New Object(props.Count - 1) {}
    For Each item As T In data
            For i As Integer = 0 To values.Length - 1
                    values(i) = props(i).GetValue(item)
            Next
            table.Rows.Add(values)
    Next
    Return table
End Function

Answer 11

我自己写了一个小库来完成这个任务。 它仅在第一次将对象类型转换为数据表时使用反射。 它发出一个方法，该方法将完成翻译对象类型的所有工作。

它的速度非常快。 你可以在这里找到它：

• GitHub 上 MoreLinq 中的 ToDataTable()
• 原文： GoogleCode 上的 ModelShredder ，合并到 MoreLinq，从 GoogleCode 移到 GitHub

Answer 12

如果您使用的是 .NET Core，则为2019 年的答案 - 使用Nuget ToDataTable 库。 好处：

• 比 FastMember 更好的性能
• 还创建结构化 SqlParameters 以用作SQL Server 表值参数

免责声明- 我是 ToDataTable 的作者

性能- 我跨越了一些Benchmark .Net测试并将它们包含在ToDataTable 存储库中。 结果如下：

创建 100,000 行数据表：

                           MacOS         Windows
Reflection                 818.5 ms      818.3 ms
FastMember from           1105.5 ms      976.4 ms
 Mark's answer
Improved FastMember        524.6 ms      456.4 ms
ToDataTable                449.0 ms      376.5 ms

Marc 的答案中建议的 FastMember 方法的性能似乎比使用反射的Mary 的答案差，但我使用 FastMember TypeAccessor 推出了另一种方法，它的性能要好得多。 尽管如此， ToDataTable包的表现仍优于同类产品。

Answer 13

将通用列表转换为数据表

使用 Newtonsoft.Json；

public DataTable GenericToDataTable(IList<T> list)
{
    var json = JsonConvert.SerializeObject(list);
    DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));
    return dt;
}

Answer 14

List<YourModel> data = new List<YourModel>();
DataTable dataTable = Newtonsoft.Json.JsonConvert.DeserializeObject<DataTable>(Newtonsoft.Json.JsonConvert.SerializeObject(data));

Answer 15

我还必须想出一个替代解决方案，因为这里列出的选项都不适用于我的情况。 我正在使用一个 IEnumerable，它返回一个 IEnumerable 并且无法枚举属性。 这做到了：

// remove "this" if not on C# 3.0 / .NET 3.5
public static DataTable ConvertToDataTable<T>(this IEnumerable<T> data)
{
    List<IDataRecord> list = data.Cast<IDataRecord>().ToList();

    PropertyDescriptorCollection props = null;
    DataTable table = new DataTable();
    if (list != null && list.Count > 0)
    {
        props = TypeDescriptor.GetProperties(list[0]);
        for (int i = 0; i < props.Count; i++)
        {
            PropertyDescriptor prop = props[i];
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
        }
    }
    if (props != null)
    {
        object[] values = new object[props.Count];
        foreach (T item in data)
        {
            for (int i = 0; i < values.Length; i++)
            {
                values[i] = props[i].GetValue(item) ?? DBNull.Value;
            }
            table.Rows.Add(values);
        }
    }
    return table;
}

Answer 16

  using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data;
using System.ComponentModel;

public partial class Default3 : System.Web.UI.Page
{
    protected void Page_Load(object sender, EventArgs e)
    {
        DataTable dt = new DataTable();
        dt = lstEmployee.ConvertToDataTable();
    }
    public static DataTable ConvertToDataTable<T>(IList<T> list) where T : class
    {
        try
        {
            DataTable table = CreateDataTable<T>();
            Type objType = typeof(T);
            PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(objType);
            foreach (T item in list)
            {
                DataRow row = table.NewRow();
                foreach (PropertyDescriptor property in properties)
                {
                    if (!CanUseType(property.PropertyType)) continue;
                    row[property.Name] = property.GetValue(item) ?? DBNull.Value;
                }

                table.Rows.Add(row);
            }
            return table;
        }
        catch (DataException ex)
        {
            return null;
        }
        catch (Exception ex)
        {
            return null;
        }

    }
    private static DataTable CreateDataTable<T>() where T : class
    {
        Type objType = typeof(T);
        DataTable table = new DataTable(objType.Name);
        PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(objType);
        foreach (PropertyDescriptor property in properties)
        {
            Type propertyType = property.PropertyType;
            if (!CanUseType(propertyType)) continue;

            //nullables must use underlying types
            if (propertyType.IsGenericType && propertyType.GetGenericTypeDefinition() == typeof(Nullable<>))
                propertyType = Nullable.GetUnderlyingType(propertyType);
            //enums also need special treatment
            if (propertyType.IsEnum)
                propertyType = Enum.GetUnderlyingType(propertyType);
            table.Columns.Add(property.Name, propertyType);
        }
        return table;
    }


    private static bool CanUseType(Type propertyType)
    {
        //only strings and value types
        if (propertyType.IsArray) return false;
        if (!propertyType.IsValueType && propertyType != typeof(string)) return false;
        return true;
    }
}

Answer 17

我意识到这已经关闭了一段时间； 但是，我对这个特定问题有一个解决方案，但需要稍作改动：需要预定义/已经实例化列和数据表。 然后我需要简单地将类型插入到数据表中。

所以这是我所做的一个例子：

public static class Test
{
    public static void Main()
    {
        var dataTable = new System.Data.DataTable(Guid.NewGuid().ToString());

        var columnCode = new DataColumn("Code");
        var columnLength = new DataColumn("Length");
        var columnProduct = new DataColumn("Product");

        dataTable.Columns.AddRange(new DataColumn[]
            {
                columnCode,
                columnLength,
                columnProduct
            });

        var item = new List<SomeClass>();

        item.Select(data => new
        {
            data.Id,
            data.Name,
            data.SomeValue
        }).AddToDataTable(dataTable);
    }
}

static class Extensions
{
    public static void AddToDataTable<T>(this IEnumerable<T> enumerable, System.Data.DataTable table)
    {
        if (enumerable.FirstOrDefault() == null)
        {
            table.Rows.Add(new[] {string.Empty});
            return;
        }

        var properties = enumerable.FirstOrDefault().GetType().GetProperties();

        foreach (var item in enumerable)
        {
            var row = table.NewRow();
            foreach (var property in properties)
            {
                row[property.Name] = item.GetType().InvokeMember(property.Name, BindingFlags.GetProperty, null, item, null);
            }
            table.Rows.Add(row);
        }
    }
}

Answer 18

如果您使用的是 VB.NET，那么这个类就可以完成这项工作。

Imports System.Reflection
''' <summary>
''' Convert any List(Of T) to a DataTable with correct column types and converts Nullable Type values to DBNull
''' </summary>

Public Class ConvertListToDataset

    Public Function ListToDataset(Of T)(ByVal list As IList(Of T)) As DataTable

        Dim dt As New DataTable()
        '/* Create the DataTable columns */
        For Each pi As PropertyInfo In GetType(T).GetProperties()
            If pi.PropertyType.IsValueType Then
                Debug.Print(pi.Name)
            End If
            If IsNothing(Nullable.GetUnderlyingType(pi.PropertyType)) Then
                dt.Columns.Add(pi.Name, pi.PropertyType)
            Else
                dt.Columns.Add(pi.Name, Nullable.GetUnderlyingType(pi.PropertyType))
            End If
        Next

        '/* Populate the DataTable with the values in the Items in List */
        For Each item As T In list
            Dim dr As DataRow = dt.NewRow()
            For Each pi As PropertyInfo In GetType(T).GetProperties()
                dr(pi.Name) = IIf(IsNothing(pi.GetValue(item)), DBNull.Value, pi.GetValue(item))
            Next
            dt.Rows.Add(dr)
        Next
        Return dt

    End Function

End Class

Answer 19

如果你的类中有属性，这行代码就可以了！！

PropertyDescriptorCollection props =
            TypeDescriptor.GetProperties(typeof(T));

但如果您拥有所有公共字段，请使用以下命令：

public static DataTable ToDataTable<T>(  IList<T> data)
        {
        FieldInfo[] myFieldInfo;
        Type myType = typeof(T);
        // Get the type and fields of FieldInfoClass.
        myFieldInfo = myType.GetFields(BindingFlags.NonPublic | BindingFlags.Instance
            | BindingFlags.Public);

        DataTable dt = new DataTable();
        for (int i = 0; i < myFieldInfo.Length; i++)
            {
            FieldInfo property = myFieldInfo[i];
            dt.Columns.Add(property.Name, property.FieldType);
            }
        object[] values = new object[myFieldInfo.Length];
        foreach (T item in data)
            {
            for (int i = 0; i < values.Length; i++)
                {
                values[i] = myFieldInfo[i].GetValue(item);
                }
            dt.Rows.Add(values);
            }
        return dt;
        }

原始答案来自上面，我只是编辑以使用字段而不是属性

并使用它执行此操作

 DataTable dt = new DataTable();
            dt = ToDataTable(myBriefs);
            gridData.DataSource = dt;
            gridData.DataBind();

Answer 20

要将通用列表转换为数据表，您可以使用DataTableGenerator

该库可让您将列表转换为具有多种功能的数据表，例如

• 翻译数据表头
• 指定要显示的一些列

Answer 21

  private DataTable CreateDataTable(IList<T> item)
        {
            Type type = typeof(T);
            var properties = type.GetProperties();

            DataTable dataTable = new DataTable();
            foreach (PropertyInfo info in properties)
            {
                dataTable.Columns.Add(new DataColumn(info.Name, Nullable.GetUnderlyingType(info.PropertyType) ?? info.PropertyType));
            }

            foreach (T entity in item)
            {
                object[] values = new object[properties.Length];
                for (int i = 0; i < properties.Length; i++)
                {
                    values[i] = properties[i].GetValue(entity);
                }

                dataTable.Rows.Add(values);
            }
            return dataTable;
        }

Answer 22

这是将列表转换为数据表的简单控制台应用程序。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.ComponentModel;

namespace ConvertListToDataTable
{
    public static class Program
    {
        public static void Main(string[] args)
        {
            List<MyObject> list = new List<MyObject>();
            for (int i = 0; i < 5; i++)
            {
                list.Add(new MyObject { Sno = i, Name = i.ToString() + "-KarthiK", Dat = DateTime.Now.AddSeconds(i) });
            }

            DataTable dt = ConvertListToDataTable(list);
            foreach (DataRow row in dt.Rows)
            {
                Console.WriteLine();
                for (int x = 0; x < dt.Columns.Count; x++)
                {
                    Console.Write(row[x].ToString() + " ");
                }
            }
            Console.ReadLine();
        }

        public class MyObject
        {
            public int Sno { get; set; }
            public string Name { get; set; }
            public DateTime Dat { get; set; }
        }

        public static DataTable ConvertListToDataTable<T>(this List<T> iList)
        {
            DataTable dataTable = new DataTable();
            PropertyDescriptorCollection props = TypeDescriptor.GetProperties(typeof(T));
            for (int i = 0; i < props.Count; i++)
            {
                PropertyDescriptor propertyDescriptor = props[i];
                Type type = propertyDescriptor.PropertyType;

                if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
                    type = Nullable.GetUnderlyingType(type);

                dataTable.Columns.Add(propertyDescriptor.Name, type);
            }
            object[] values = new object[props.Count];
            foreach (T iListItem in iList)
            {
                for (int i = 0; i < values.Length; i++)
                {
                    values[i] = props[i].GetValue(iListItem);
                }
                dataTable.Rows.Add(values);
            }
            return dataTable;
        }
    }
}

Answer 23

Se probó el método para que acepte campos con null。

// remove "this" if not on C# 3.0 / .NET 3.5
    public static DataTable ToDataTable<T>(IList<T> data)
    {
        PropertyDescriptorCollection props =
            TypeDescriptor.GetProperties(typeof(T));
        DataTable table = new DataTable();
        Type Propiedad = null;
        for (int i = 0; i < props.Count; i++)
        {
            PropertyDescriptor prop = props[i];
            Propiedad = prop.PropertyType;
            if (Propiedad.IsGenericType && Propiedad.GetGenericTypeDefinition() == typeof(Nullable<>)) 
            {
                Propiedad = Nullable.GetUnderlyingType(Propiedad);
            }
            table.Columns.Add(prop.Name, Propiedad);
        }
        object[] values = new object[props.Count];
        foreach (T item in data)
        {
            for (int i = 0; i < values.Length; i++)
            {
                values[i] = props[i].GetValue(item);
            }
            table.Rows.Add(values);
        }
        return table;
    }

Answer 24

 Dim counties As New List(Of County)
 Dim dtCounties As DataTable
 dtCounties = _combinedRefRepository.Get_Counties()
 If dtCounties.Rows.Count <> 0 Then
    For Each row As DataRow In dtCounties.Rows
      Dim county As New County
      county.CountyId = row.Item(0).ToString()
      county.CountyName = row.Item(1).ToString().ToUpper()
      counties.Add(county)
    Next
    dtCounties.Dispose()
 End If

Answer 25

我认为它更方便，更易于使用。

   List<Whatever> _lobj= new List<Whatever>(); 
    var json = JsonConvert.SerializeObject(_lobj);
                DataTable dt = (DataTable)JsonConvert.DeserializeObject(json, (typeof(DataTable)));

Answer 26

最简单的答案可能是这个：

[ https://stackoverflow.com/a/60776314/10235747][1]

Answer 27

如果您想使用反射并设置列顺序/仅包含某些列/排除某些列，请尝试以下操作：

        private static DataTable ConvertToDataTable<T>(IList<T> data, string[] fieldsToInclude = null,
string[] fieldsToExclude = null)
    {
        PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(typeof(T));
        DataTable table = new DataTable();
        foreach (PropertyDescriptor prop in properties)
        {
            if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
                (fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
                continue;
            table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
        }

        foreach (T item in data)
        {
            var atLeastOnePropertyExists = false;
            DataRow row = table.NewRow();
            foreach (PropertyDescriptor prop in properties)
            {

                if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
                    continue;

                row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
                atLeastOnePropertyExists = true;
            }

            if(atLeastOnePropertyExists) table.Rows.Add(row);
        }


        if (fieldsToInclude != null)
            SetColumnsOrder(table, fieldsToInclude);

        return table;

    }

    private static void SetColumnsOrder(DataTable table, params String[] columnNames)
    {
        int columnIndex = 0;
        foreach (var columnName in columnNames)
        {
            table.Columns[columnName].SetOrdinal(columnIndex);
            columnIndex++;
        }
    }

Answer 28

您可以尝试以下操作

public static DataTable GetDataTableFromObjects(object[] objects)

    {

        if (objects != null && objects.Length > 0)

        {

            Type t = objects[0].GetType();
            DataTable dt = new DataTable(t.Name);
            foreach (PropertyInfo pi in t.GetProperties())
            {
                dt.Columns.Add(new DataColumn(pi.Name));
            }
            foreach (var o in objects)
            {
                DataRow dr = dt.NewRow();
                foreach (DataColumn dc in dt.Columns)
                {
                    dr[dc.ColumnName] = o.GetType().GetProperty(dc.ColumnName).GetValue(o, null);

                }
                dt.Rows.Add(dr);
            }

            return dt;
        }

        return null;

    }

Answer 29

清单篮；

字符串 json = JsonConvert.SerializeObject(Basket, Formatting.Indented);

    DataTable dtUsingMethod = Business.GetJSONToDataTableUsingNewtonSoftDll(json);

公共静态数据表 GetJSONToDataTableUsingNewtonSoftDll(string JSONData) { DataTable dt = (DataTable)JsonConvert.DeserializeObject(JSONData, (typeof(DataTable))); 返回 dt; }

Answer 30

这是列表中的另一个。 Cinchoo ETL - 一个将可枚举转换为数据表的开源库。

List<Whatever> whatever = new List<Whatever>();
var dt = whatever.AsDataTable();

免责声明：我是这个库的作者。

Answer 31

列出任何内容 = new List(); var datatable =whatever.ConvertToDataTable();