[英]Xml Deserialize return null
我有下面的类,其中包含我要反序列化xml的类的对象。 我正在使用以下技术显示为空。 实际上,我想对问题的最后一部分中的xml定义进行反序列化。 为此,我使用以下技术可能是我走错了路,请纠正我
[Serializable]
public class Param
{
public Professor Professor { get; set; }
public Course Course { get; set; }
}
public class Professor
{
public int id;
public String name;
public Professor() { }
}
public class Course
{
public int id;
public String name;
public Course() { }
}
以下是反序列化的C#代码,从文件schedule.xml读取xml的xml示例在下面定义
string path = "//schedule.xml";
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "param";
xRoot.IsNullable = true;
XmlSerializer serializer = new XmlSerializer(typeof(Param),xRoot);
using (StreamReader reader = new StreamReader(path))
{
param = (Param)serializer.Deserialize(reader);
}
这是schedule.xml文件中定义的xml示例
<param>
<professor id='1' name='Novak J.'></professor>
<Professor id='2' name='Stanek A.'> </Professor>
<course id='1' name='Mathematics' biolab='false'> </course>
<course id='2' name='Biology' biolab='true'> </course>
</param>
像这样更改您的课程,然后重试。 这是VS为您的xml生成的代码。 我使用您的xml结构进行了测试,并且可以正常工作。 但是您可能需要再次为完整的xml重新生成代码。
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class param
{
private paramProfessor professorField;
private paramProfessor1 professorField1;
private paramCourse[] courseField;
/// <remarks/>
public paramProfessor professor
{
get
{
return this.professorField;
}
set
{
this.professorField = value;
}
}
/// <remarks/>
public paramProfessor1 Professor
{
get
{
return this.professorField1;
}
set
{
this.professorField1 = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("course")]
public paramCourse[] course
{
get
{
return this.courseField;
}
set
{
this.courseField = value;
}
}
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class paramProfessor
{
private byte idField;
private string nameField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public byte id
{
get
{
return this.idField;
}
set
{
this.idField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string name
{
get
{
return this.nameField;
}
set
{
this.nameField = value;
}
}
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class paramProfessor1
{
private byte idField;
private string nameField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public byte id
{
get
{
return this.idField;
}
set
{
this.idField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string name
{
get
{
return this.nameField;
}
set
{
this.nameField = value;
}
}
}
/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class paramCourse
{
private byte idField;
private string nameField;
private bool biolabField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public byte id
{
get
{
return this.idField;
}
set
{
this.idField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string name
{
get
{
return this.nameField;
}
set
{
this.nameField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public bool biolab
{
get
{
return this.biolabField;
}
set
{
this.biolabField = value;
}
}
}
您的示例XML:
<param>
<professor id='1' name='Novak J.'></professor>
<professor id='2' name='Stanek A.'> </professor>
<course id='1' name='Mathematics' biolab='false'> </course>
<course id='2' name='Biology' biolab='true'> </course>
</param>
可序列化的类:
[XmlRoot(Namespace = "", ElementName = "param")]
public class Param
{
[XmlElement("professor")]
public List<professor> Professor { get; set; }
[XmlElement("course")]
public List<course> Course { get; set; }
}
public class professor
{
[XmlAttribute("id")]
public int professorid;
[XmlAttribute("name")]
public string professorname;
public professor() { }
}
public class course
{
[XmlAttribute("id")]
public int courseid;
[XmlAttribute("name")]
public string coursename;
public course() { }
}
调用反序列化代码:
DeserializeFromXml<Param>(XMLinStringVariable);
反序列化的C#代码:
public static T DeserializeFromXml<T>(string xml)
{
try
{
T result;
XmlSerializer ser = new XmlSerializer(typeof(T));
using (TextReader tr = new StringReader(xml))
{
result = (T)ser.Deserialize(tr);
}
return result;
}
catch { throw; }
}
编辑 :错误在于<professor>
和<course>
标记都使用相同的属性名称。 因此,我在序列化类中添加了XmlElement
和XmlAttribute
标记以对它们进行分叉。
您必须在类中将id和name标记为XML Attribute,以便在反序列化期间选择值。 我还重组了您的XML。 看看下面
static void Main(string[] args)
{
string xml = File.ReadAllText(path of the file);
Param p = DeserializeFromXml<Param>(xml);
}
public static T DeserializeFromXml<T>(string xml)
{
try
{
T result;
XmlSerializer ser = new XmlSerializer(typeof(T));
using (TextReader tr = new StringReader(xml))
{
result = (T)ser.Deserialize(tr);
}
return result;
}
catch { throw; }
}
}
[Serializable]
[XmlRoot(Namespace = "", ElementName = "param")]
public class Param
{
[XmlArray("professors")]
public List<professor> Professor { get; set; }
[XmlArray("courses")]
public List<course> Course { get; set; }
}
public class professor
{
[XmlAttribute("id")]
public int id { get; set; }
[XmlAttribute("name")]
public string name { get; set; }
public professor() { }
}
public class course
{
[XmlAttribute("id")]
public int id { get; set; }
[XmlAttribute("name")]
public string name { get; set; }
public course() { }
}
新的XML
<param>
<professors>
<professor id='1' name='Novak J.'></professor>
<professor id='2' name='Stanek A.'> </professor>
</professors>
<courses>
<course id='1' name='Mathematics' biolab='false'> </course>
<course id='2' name='Biology' biolab='true'> </course>
</courses>
</param>
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