[英]sum all value in foreach loop php
echo array_sum(array_filter(array_map(function($row){
if($row->date == '02-01-2016')
return $row->cost;
}, $array)));
您可以使用
array_map
:比较和跳过不需要总计的成本值。 array_filter
:然后删除空白索引 array_sum
:最后求和 注意:如果您要从数据库中获取结果,则可以在此处简单地求和(如下所示):
$db->query("SELECT SUM(costs) FROM table_name WHERE `date`='2016-01-02'");
echo $db->fetchColumn();
试试下面的代码:
<?php
$total = 0;
foreach((array)$query as $row):
$date = $row->date;
$cost = $row->cost;
if(date("M-d-Y", strtotime($date))==date("M-d-Y")) {
$total = $total+$cost;
}
?>
<td><?php echo $date ?></td>
<td><?php echo $cost ?></td>
<?php endforeach; ?>
<td colspan="2"><?php echo $total; ?></td>
<?php
$tot = 0;
foreach( (array)$query as $row ) {
if( $row->date=='02-01-2016' ) $tot = $tot+$row->cost;
?>
<tr>
<td><?php echo $row->date ?></td>
<td><?php echo $row->cost ?></td>
</tr>
<?php } ?>
<tr><td colspan="2"><?php echo $tot; ?></td></tr>
显然,如果$row->date
的格式设置为dd-mm-yyyy
,则比较有效
<table border=1>
<?php
$tot = 0;
foreach($query as $row ) {
if( $row->date=='2016-01-02' ) $tot += $row->cost;
?>
<tr>
<td><?php echo $row->date ?></td>
<td><?php echo $row->cost ?></td>
</tr>
<?php } ?>
<tr><td></td><td><?php echo $total; ?></td></tr>
</table>
它会为您完美地满足您的需求。
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