[英]How to retrieve data from MySQL database and display value in a text field
我想从下表中检索信息并将其显示在文本字段中
我有一个名为items
的表。 在items
我具有以下字段: item_number
, description
, item_id
, custom1
, custom2
, custom3
, custom4
如何回显或打印自定义字段的值?
mysql_connect("####", "####", "####") or die(mysql_error());
mysql_select_db("####") or die(mysql_error());
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM items") or die(mysql_error());
while($row = mysql_fetch_array($result))
{
echo '<input type="text" value='.$row['custom1'].'><br/>';
}
<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "sandbox";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT item_number, description, custom1, another_field FROM items";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<p>item_number: " . $row["item_number"]. "<br />description:" . $row["description"]. "<br />custom1: " . $row["custom1"] . "<br />another_field: " . $row["another_field"] . "</p>";
}
} else {
echo "0 results";
}
$conn->close();
?>
这是我的代码
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT custom1, custom2, custom3 FROM ospos_items ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
echo "custom:" . $row["custom1"]. " custom2: " . $row["custom2"]. " custom3 :" . $row["custom3"]. "<br>";
}
} else {
echo "0 results";
}
$ conn-> close(); ?>
它输出thid
我需要它仅输出所选项目的海关字段,因此我添加
$ sql =“从ospos_items中选择custom1,custom2,custom3,其中item_id ='item_id'”;
因为那是唯一的数字,但它输出0 resuls,我在想是否需要一个数组或其他东西来使它工作,但我是php新手,所以我使用item_id,因为它在表中列出
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