[英]Else Statement in PHP
我正在学习PHP,并编写了一个简单的翻译器。
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Translator</title> </head> <body> <form method="post" action=""> <input type="string" name="word"> <input type="submit"> </form> <?php if (isset($_POST["word"])) { $word = $_POST["word"]; echo $word . " -> "; function translate($word){ $dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai'); foreach ($dict as $en => $th) { if ($word == $en) { echo $th; break; } } } translate($word); } else { echo "enter a word"; } ?> </body> </html>
输入不在数组中的单词时,如何显示字符串“ not in dictionary”? 对于改进代码的任何反馈或建议,我也将不胜感激。
PHP为此提供了一个函数in_array
。 您可以执行以下操作:
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!in_array($word, array_keys($dict))){
echo '"' . $word . '" not found in the dictionary.';
}else{
echo $dict[$word];
}
编辑:改进
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(!array_key_exists(strtolower($word), $dict)){
echo '"' . $word . '" not found in the dictionary.';
}else{
echo $dict[$word];
}
更改您的功能代码
function translate($word){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if(array_key_exists($word, $dict)){
echo $dict[$word];
}else{
echo 'not in dictionary';
}
}
如果找到一个单词时返回函数的值,否则您可以对结果进行逻辑测试以显示替代错误消息。
<form method="post" action="">
<input type="string" name="word">
<input type="submit">
</form>
<?php
if( $_SERVER['REQUEST_METHOD']=='POST' ){
if ( isset( $_POST["word"] ) ) {
$word = $_POST["word"];
echo $word . " -> ";
function translate( $word=false ){
if( $word ){
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
foreach ($dict as $en => $th) {
if( $word == $en ) {
return $th;
}
}
}
return false;
}
$result=translate( $word );
echo $result ? $result : 'Sorry, not found!';
} else {
echo "enter a word";
}
}
?>
您可以使用array_key_exist:
$dict = array('hello' => 'sawadee khap','thanks' => 'kap khum khap','sorry' => 'mai pen rai');
if (array_key_exists($word, $dict)) {
//in dictionary
}else{
//not in dictionary
}
请尝试这个
<form method="post" action="">
<input type="string" name="word">
<input type="submit">
</form>
<?php
function translate($word) {
$dict = array('hello' => 'sawadee khap', 'thanks' => 'kap khum khap', 'sorry' => 'mai pen rai');
if (array_key_exists($word, $dict)) {
echo $dict[$word];
} else {
echo " not in dictionary";
}
}
if (isset($_POST["word"])) {
$word = $_POST["word"];
echo $word . " -> ";
translate($word);
} else {
echo "enter a word";
}
?>
您的top if语句缺少括号。
关于您的问题,我认为您想浏览字典,如果找不到该词来回显它。 您可以使用一个标志。 将其设置为for循环之前的内容,然后在找到单词时将其设置为其他内容。 然后检查for循环的末尾,例如:
$found = false;
foreach ($dict as $en => $th) {
if ($word == $en) {
$found = true'
echo $th;
break;
}
}
if (!$found) echo $word;''
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