[英]MySQL Error 1064: Creating a procedure
我正在修改我的程序。 由于我切换到另一个Webspace提供程序,并且它们不允许使用SQL-Trigger,因此我需要在过程中执行以下操作:
在为招聘创建评论后,必须更新招聘“最后活动”字段。 创建的评论ID也应返回。
我尝试了这个:
BEGIN
DECLARE id INT;
INSERT INTO
`comments` (
`comments`.`recruitment_id`,
`comments`.`user_id`,
`comments`.`comment`
)
VALUES (
recruitment_id,
user_id,
com
);
SELECT
LAST_INSERTED_ID()
INTO
id;
UPDATE
`recruitments`
SET
`recruitments`.`lastActivity` = `comments`.`creationDate`
INNER JOIN
`comments`
ON
`recruitments`.`id` = `comments`.`recruitment_id`
WHERE
`comments`.`id` = id;
SELECT id;
END
但是我得到一个错误:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INNER JOIN `comments` ON `recruitments`.`id` = `comments`' at line 25
我敢打赌,这只是一个小错误,但我似乎找不到它=(
尝试像这样编写主体:
BEGIN
DECLARE v_id INT;
INSERT INTO comments(recruitment_id, user_id, comment)
VALUES (v_recruitment_id, v_user_id, v_com);
SELECT v_id := LAST_INSERTED_ID();
UPDATE recruitments r INNER JOIN
comments c
ON r.id = c.recruitment_id
SET r.lastActivity = c.creationDate
WHERE c.id = v.id;
SELECT v_id;
END;
您的查询存在几个问题:
select
的列列表中的列名称。 join
update
的正确语法是在update
之后放置join
逻辑。
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.