[英]How do I get the first option of a select box to display in a div automatically when the page loads with JavaScript/jQuery?
[英]How do I automatically display the first google image on my page?
我有一个页面,该页面会自动从MySQL数据库中检索两个随机条目,并在每次刷新页面时要求用户对其进行比较。 如何将这两个字符串自动转换为第一个Google图片结果? 这是我到目前为止的内容:
<?php //I retrieve the names and group names here//
$firstpersonaName = (string) $row["personaName"];
$firstpersonaGroupName = (string) $row["groupName"];
$firstpersonaGroupNameForGoogle = preg_split('( )', $firstpersonaGroupName);
?> //then convert any group names containing spaces into arrays here//
<?php //then here I build the query that displays a google image page//
$newname = '';
foreach ($firstpersonaGroupNameForGoogle as $firstpersonaPartofGroupName) {
$newname = $firstpersonaPartofGroupName . '+';
}
$newname = rtrim($newname, "+");
echo "https://www.google.com/search?q=" . $firstpersonaName . "+" . $newname . '&tbm=isch';
?>
这给了我类似的东西: https : //www.google.com/search?q=charlie+always+sunny&tbm=isch
那么,如何获取该链接并将其转换为第一张图片的链接? 还是前几对夫妇中的任何一个。 (在这种情况下: http : //cdn3.denofgeek.us/sites/denofgeekus/files/sunny_0.jpg )
好的,这就是我最终要为每个查询随机生成两张图片的目的:
首先,我下载了该文件并将其添加到与网页相同的目录中: http : //simplehtmldom.sourceforge.net/
然后,我只是在想要显示图片的div中添加了此PHP代码:
<?php
// Include the php dom parser
include_once 'simple_html_dom.php';
//build the google images query
$newname = '';
foreach ($firstpersonaGroupNameForGoogle as $firstpersonaPartofGroupName) {
$newname = $firstpersonaPartofGroupName . '+';
}
$newname = rtrim($newname, "+");
//echo "https://www.google.com/search?q=" . $firstpersonaName . "+" . $newname . '&tbm=isch';
$newname = "https://www.google.com/search?q=" . $firstpersonaName . "+" . $newname . '&tbm=isch';
//use parser on queried page
$html = file_get_html($newname);
//echo $html;
//create an array for all pics on page
$picarray = array();
$picurl = '';
// Find all images
foreach($html->find('img') as $element) {
//echo $element->src . '<br>';
$picurl = $element->src;
array_push($picarray,$picurl);
}
//then pick two random ones
$picurl = $picarray[array_rand($picarray)];
echo "<img src=" . $picurl . ">";
$picurl = $picarray[array_rand($picarray)];
echo "<img src=" . $picurl . ">";
?>
它们的分辨率很小(约150像素),但实际上与我想做的一样很好。 如果您想获取一个非缩略图图片,那是完全不同的蠕虫罐头。
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