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[英]Haskell: Usage of flip results in error: Equations for ‘.>’ have different numbers of arguments
[英]error: Equations for ‘det’ have different numbers of arguments
我正在尝试计算行列式,并且定义了det
函数,如下所示:
det :: (Double,Double) -> (Double,Double) -> Double
det _ = 0.0
det [] = error "its Empty!"
det [x] = error "contains only one point!"
det (x1, y1) (x2, y2) = (x1*y2 + x2*y1)
我收到以下错误
Equations for ‘det’ have different numbers of arguments
PolygonArea.hs:11:1-11
PolygonArea.hs:14:1-39
Failed, modules loaded: none.
首先,类型(Double, Double)
始终是两个Double
的对,永远不会是空列表或单例列表。 其次,就像错误消息中所说的那样,您的det
案例需要具有相同数量的参数,但是前三个给出了一个,而第四个给出了两个。
修复所有这些,您将获得
det :: (Double, Double) -> (Double, Double) -> Double
det (x1, y1) (x2, y2) = (x1 * y2 + x2 * y1)
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