PHP的形式不发送日期通过数据库SQL

Question

我已经使用HTML和PHP设置了表单。 我将从表单提交的所有信息发送到SQL数据库。 提交表单时，出现以下错误代码：

ERROR: Could not execute INSERT INTO `timesheets` (`Name`, `weekending`, `monin`, `monout`, `tuein`, `tueout`, `wedin`, `wedout`, `thursin`, `thursout`, `friin`, `friout`, `satin`, `satout`, `sunin`, `sunout`) VALUES ('Nathan Langer','07:30','16:00','18:00','19:00','06:30','15:00','03:00','16:00','05:00','16:00','00:00','00:00','00:00','00:00'). Column count doesn't match value count at row 1

如您所见，日期没有被推迟（应该在Nathan Langer和07:30之间。

我的提交代码如下：

<?php
/* Attempt MySQL server connection. Assuming you are running MySQL
server with default setting (user 'root' with no password) */
$link = mysqli_connect("localhost", "username", "pass", "dbname");

// Check connection
if($link === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}

// Escape user inputs for security
$Name = mysqli_real_escape_string($link, $_POST['Name']);
$insertdate = date('Y-m-d', strtotime($_POST['weekending']));
$monin = mysqli_real_escape_string($link, $_POST['monin']);
$monout = mysqli_real_escape_string($link, $_POST['monout']);
$tuein = mysqli_real_escape_string($link, $_POST['tuein']);
$tueout = mysqli_real_escape_string($link, $_POST['tueout']);
$wedin = mysqli_real_escape_string($link, $_POST['wedin']);
$wedout = mysqli_real_escape_string($link, $_POST['wedout']);
$thursin = mysqli_real_escape_string($link, $_POST['thursin']);
$thursout = mysqli_real_escape_string($link, $_POST['thursout']);
$friin = mysqli_real_escape_string($link, $_POST['friin']);
$friout = mysqli_real_escape_string($link, $_POST['friout']);
$satin = mysqli_real_escape_string($link, $_POST['satin']);
$satout = mysqli_real_escape_string($link, $_POST['satout']);
$sunin = mysqli_real_escape_string($link, $_POST['sunin']); 
$sunout = mysqli_real_escape_string($link, $_POST['sunout']);


// attempt insert query execution
$sql = "INSERT INTO `timesheets` (`Name`, `weekending`, `monin`, `monout`,      `tuein`, `tueout`, `wedin`, `wedout`, `thursin`, `thursout`, `friin`, `friout`, `satin`, `satout`, `sunin`, `sunout`) VALUES ('$Name','$monin','$monout','$tuein','$tueout','$wedin','$wedout','$thursin','$thursout','$friin','$friout','$satin','$satout','$sunin','$sunout')";
if(mysqli_query($link, $sql)){
header('location:timesheets.php');
} else{
echo "ERROR: Could not execute $sql. " . mysqli_error($link);
}

// close connection
mysqli_close($link);
?>

这是因为我对提交表单中的日期做错了吗？ 表单中的日期字段如下：

<div class="col-md-6 col-sm-6" >
<div class="input-group">
<span class="input-group-addon">
<i class="fa fa-calendar"></i>
</span>
<input type="date" id="weekending" class="form-control " name="weekending" placeholder="Week Ending">
</div>                                              
</div>  

请有人可以帮助我找到问题所在以及为什么它不会发布到数据库吗？

Answer 1

从

$sql = "INSERT INTO `timesheets` (`Name`, `weekending`, `monin`, `monout`,`tuein`, `tueout`, `wedin`, `wedout`, `thursin`, `thursout`, `friin`, `friout`, `satin`, `satout`, `sunin`, `sunout`) VALUES ('$Name','$monin','$monout','$tuein','$tueout','$wedin','$wedout','$thursin','$thursout','$friin','$friout','$satin','$satout','$sunin','$sunout')";

至

$sql = "INSERT INTO `timesheets` (`Name`, `weekending`, `monin`, `monout`,`tuein`, `tueout`, `wedin`, `wedout`, `thursin`, `thursout`, `friin`, `friout`, `satin`, `satout`, `sunin`, `sunout`) VALUES ('$Name','$insertdate','$monin','$monout','$tuein','$tueout','$wedin','$wedout','$thursin','$thursout','$friin','$friout','$satin','$satout','$sunin','$sunout')";

Answer 2

您传递的列多于否。 价值

因此，您需要通过添加一个以上的列名或删除一个值来更正查询。

INSERT INTO `timesheets` (`Name`, `weekending`, `monin`, `monout`, `tuein`, 
`tueout`, `wedin`, `wedout`, `thursin`, `thursout`, `friin`, `friout`, 
`satin`, `satout`, `sunin`, `sunout`) VALUES ('Nathan 
Langer','07:30','16:00','18:00','19:00','06:30','15:00','03:00','16:00','05:00',
'16:00','00:00','00:00','00:00','00:00', '00:00')

上面的代码将随着我在其中添加更多价值而工作。