[英]MySQL Distinct Poor performance
我有一个带有多个左连接的Distinct Select语句,当我的where子句很大时,该语句的性能很差。 以下是我的声明
SELECT DISTINCT u.*, ri.id as reg_id, d.id as dist_id
FROM users u
LEFT JOIN earned_points ep ON u.id = ep.user_id
LEFT JOIN distributors d ON d.id = ep.distributor_id
OR d.id = u.distributor_id
OR d.id = u.additional_distributor_id
LEFT JOIN registration_items_users riu ON u.id = riu.user_id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21
LEFT JOIN registration_items ri ON riu.registration_item_id = ri.id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931 );
此查询大约需要4秒钟才能完成。 如果我将where减少到一个id,那么它最多可以加速170ms。
将不胜感激有关如何使此查询更快的任何建议。
谢谢
编辑
我能够根据Rick James(接受的答案)的建议提出一个解决方案。 使用Union并摆脱Left Joins and Distinct可以达到目的。 与上面的4秒版本相比,此新查询大约需要200毫秒。
(SELECT u.*,
(SELECT riu.registration_item_id
FROM registration_items_users riu
WHERE riu.user_id = u.id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21) as reg_id,
d.id as dist_id
FROM users u
JOIN earned_points ep ON u.id = ep.user_id
JOIN distributors d ON d.id = ep.distributor_id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931))
UNION
(SELECT u.*,
(SELECT riu.registration_item_id
FROM registration_items_users riu
WHERE riu.user_id = u.id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21) as reg_id,
d.id as dist_id
FROM users u
JOIN distributors d ON d.id = u.distributor_id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931))
UNION
(SELECT u.*,
(SELECT riu.registration_item_id
FROM registration_items_users riu
WHERE riu.user_id = u.id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21) as reg_id,
d.id as dist_id
FROM users u
JOIN distributors d ON d.id = u.additional_distributor_id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931))
在EXPLAIN
,查看u
行。 它正在执行大约6974行的“表扫描”。
除非“ right”表是可选的,否则请摆脱LEFT
。
将OR
变成UNION
; 那就是索引使您失败的地方。 ( UNION ALL
比UNION DISTINCT
快;请选择任何一个有意义的。)
假设可以删除LEFTs
,并且可以将DISTINCT
从SELECT
移到UNION
:
SELECT u.*, ri.id as reg_id, d.id as dist_id
FROM users u
JOIN earned_points ep ON u.id = ep.user_id -- ep needed only for this
JOIN distributors d ON d.id = ep.distributor_id -- This one line differs
JOIN registration_items_users riu ON u.id = riu.user_id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21
JOIN registration_items ri ON riu.registration_item_id = ri.id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931
)
UNION DISTINCT
SELECT u.*, ri.id as reg_id, d.id as dist_id
FROM users u
JOIN distributors d ON d.id = u.distributor_id
JOIN registration_items_users riu ON u.id = riu.user_id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21
JOIN registration_items ri ON riu.registration_item_id = ri.id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931
)
UNION DISTINCT
SELECT u.*, ri.id as reg_id, d.id as dist_id
FROM users u
JOIN distributors d ON d.id = u.additional_distributor_id
JOIN registration_items_users riu ON u.id = riu.user_id
AND riu.distributor_id = d.id
AND riu.registration_item_id = 21
JOIN registration_items ri ON riu.registration_item_id = ri.id
WHERE d.id IN (201,281,321,631,901,971,1211,1601,1611,1621,
1631,1641,1651,1661,1671,1681,1691,1701,1711,1721,1731,
1741,1751,1761,1771,1781,2281,2291,2401,2781,2801,2931
) ;
跨列展开数组通常是一个坏主意。 这似乎是distributors
正在发生的事情。 这种混乱可能是这种情况的结果。
编辑
更好的是将ri
和rui
内容从选择中拉出,并将其转换为子查询。 这是要点; 我没有精力写这一切:
SELECT x.*,
( SELECT ... ri and rui stuff ... ) AS reg_id
FROM (
-- from above, less the ri and rui stuff:
SELECT ...
UNION DISTINCT
SELECT ...
UNION DISTINCT
SELECT ...
) AS x;
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