[英]XPATH executing complex queries
如何在给定的xml上执行以下查询:
XML在这里:
<node1>
<node2>
<node3>
<id>ABC-123</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task3" operation="and" value="hij" />
<task name="task4" operation="or" value="klm" />
<task name="task5" operation="and" value="nop" />
<task name="task6" value="uvw" />
</condition>
</node3>
<node3>
<id>XYZ-987</id>
<condition>
<task name="task1" operation="and" value="cde" />
<task name="task2" operation="and" value="abc" />
<task name="task5" operation="and" value="nop" />
</condition>
</node3>
<node3>
<id>RST-567</id>
<condition>
<task name="task1" operation="and" value="abc" />
<task name="task2" operation="and" value="efg" />
<task name="task8" operation="and" value="jkl" />
<task name="task9" operation="and" value="rst" />
<task name="task10" value="xyz" />
</condition>
</node3>
<node3>
<id>PQR-345</id>
<condition>
<task name="task1" operation="and" value="ijk" />
<task name="task2" operation="and" value="klm" />
<task name="task8" operation="and" value="jkl" />
<task name="task9" operation="and" value="rst" />
</condition>
</node3>
</node2>
</node1>
我尝试了以下规则,但结果为空
String expression = "/node1/node2/node3/id[following-sibling::condition/task[(@name='task1' and @value='cde') and (@name='task2' and @value='abc')]]"
我从如何使用XPATH解析XML中获得了上述表达式
以上两种情况的表达是什么?
您的xpath不起作用的原因是因为您的谓词[(@name='task1' and @value='cde') and (@name='task2' and @value='abc')]
在同一位置执行任务节点,如果@name
= 'task1'
则@name
永远不会是'task2'
。
相反,您应该创建谓词,该谓词将在所有相关节点上运行/检查,如下所示:
如果(task1 = cde && task2 = abc)我会得到id = XYZ-987
/node1/node2/node3[condition/task[@name='task1' and @value='cde'] and condition/task[@name='task2' and @value='abc']]/id
如果((task1 = abc && task2 = efg)|| task5 = nop)我会得到id = ABC-123,XYZ-987,RST-567
/node1/node2/node3[condition/task[@name='task1' and @value='abc'] and condition/task[@name='task2' and @value='efg'] or condition/task[@name='task5' and @value='nop']]/id
你可以包括你的括号,如果你想要的,但在布尔运算, and
参数总是之前评估or
论证,所以他们在这种情况下没有必要: /node1/node2/node3[(condition/task[@name='task1' and @value='abc'] and condition/task[@name='task2' and @value='efg']) or condition/task[@name='task5' and @value='nop']]/id
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