[英]jQuery - Wrap every two elements within a div
我有以下jQuery:-
var userFeed = new Instafeed({
get: 'user',
userId: 'XXXXXXXX',
accessToken: 'XXXXXXXXXXXXXXXXXX',
template: '',
resolution: 'standard_resolution',
limit: 20,
sortBy: 'most-recent',
after: function() {
$('#instafeed > div:nth-child(1)').addClass('active');
},
success: function(data) {
$('#instafeed > div:nth-child(1)').addClass('active');
$('.carousel').carousel({interval:3000});
for (var i = 0; i < $(data.data).size(); i++) {
$('.carousel-inner').append('<div class="item"></div>');
$('.item').append('<img class="img-insta" src='+data.data[i].images.standard_resolution.url+'>');
}
}
});
userFeed.run();
此刻的输出是:
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
</div>
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
</div>
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
</div>
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
</div>
我要实现的是:
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
</div>
<div class="item">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838423_1391175941177184_1399748988_n.jpg?ig_cache_key=ODgwMzgxNzMwMjgwNTA1MzE0.2">
<img class="img-insta" src="https://scontent.cdninstagram.com/t51.2885-15/e15/10838931_1585587768341057_2123046132_n.jpg?ig_cache_key=ODY4NzA0NDk3ODQxMjc0ODA4.2">
</div>
因此,它将两个图像包装在<div class="item"></div>
有任何想法吗?
尝试像这样重写您的逻辑,
var car=$('.carousel-inner'), itm;
for (var i = 0; i < $(data.data).length; i++) {
if(i%2==0){
itm = $('<div class="item"></div>');
car.append(itm);
}
itm.append('<img class="img-insta" src='+data.data[i].images.standard_resolution.url+'>');
}
而且,如果您使用的jQuery版本高于1.8
,则不要使用.size()
。 由于已弃用。 使用.length
代替
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.