[英]How does the 'prototype' object have access to the newly created object for 'this'?
[英]Does JS prototype have access to the argument(s) passed to an object during initialization?
一切都在标题中……我知道使用原型创建的函数无法访问私有对象的数据/函数,但是访问在创建对象时传递给对象的参数又如何呢?
var Voice = function (word)
{
/*
I know I can obviously do something like : 'this.word = word;'
But I was wondering whether there is a standard way of calling an
argument from within a prototype function without having to do
the above ?
*/
};
Voice.prototype.speak = function ()
{
console.log({{word}});
};
x = new Voice('all I can say is this');
x.speak();
谢谢!
没有。
原型中的函数未在变量所涉及的函数中定义,因此它们无法访问它们。
您可以将变量存储为对象属性,然后从那里读取它。
this.word = word;
也许是这样的:
var Voice = function (word) { this.init_word = word; }; Voice.prototype.speak = function (){ console.log(this.init_word); }; x = new Voice('all I can say is this'); x.speak();
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