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在Android中的ShouldInterceptRequest中的WebView中获取响应标头

[英]Get response headers in webview in shouldInterceptRequest in Android

当我向服务器发布一些URL时,我试图在webview中获取响应头。 我正在使用shouldInterceptRequest方法。

@Override 
        public WebResourceResponse shouldInterceptRequest(final WebView view, final WebResourceRequest request) {

            if(request.getUrl().toString().contains(SMConstant.INTERCEPTED_URL)){
                if(interceptFlag==0){
                    ((Activity) mContext).runOnUiThread(new Runnable(){
                        @Override
                        public void run() {
                            view.postUrl(request.getUrl().toString(), EncodingUtils.getBytes(postData, "UTF-8"));
                        }
                    });
                    interceptFlag++;
                }

            }
            return super.shouldInterceptRequest(view, request);
        }

此方法返回WebResourceResponse对象。 但是我没有办法从中获取响应头。

默认情况下return super.shouldInterceptRequest(view, request); 返回null。

因此,应该采取什么措施才能捕获实际的Webview响应。

尝试以下代码(需要API版本21):

@RequiresApi(api = Build.VERSION_CODES.LOLLIPOP)
        @Override
        public WebResourceResponse shouldInterceptRequest(WebView view, WebResourceRequest request) {
            if (request.getUrl().toString().contains("some_char")) {// condition to intercept webview's request
                return handleIntercept(request);
            } else
                return super.shouldInterceptRequest(view, request);
        }
@RequiresApi(api = Build.VERSION_CODES.LOLLIPOP)
private WebResourceResponse handleIntercept(WebResourceRequest request){
    OkHttpClient okHttpClient = new OkHttpClient();
    final Call call = okHttpClient.newCall(new Request.Builder()
            .url(request.getUrl().toString())
            .method(request.getMethod(),null)
            .headers(Headers.of(request.getRequestHeaders()))
            .build()
    );
    try {
        final Response response = call.execute();
        response.headers();// get response header here
        return new WebResourceResponse(
                response.header("content-type", "text/plain"), // You can set something other as default content-type
                response.header("content-encoding", "utf-8"),  //you can set another encoding as default
                response.body().byteStream()
        );
    } catch (IOException e) {
        e.printStackTrace();
        return null
    }
}

参考: 访问WebView中的http响应标头?

https://artemzin.com/blog/use-okhttp-to-load-resources-for-webview/

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